Question

我有以下JSON字符串：

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{"name":"Marine Lines","location_id":3},{"name":"Ghatkopar","location_id":2}

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我希望location_id为

3,2

Answer 1

简单：

var data = [{"name":"Marine Lines","location_id":3},{"name":"Ghatkopar","location_id":2}]
var result = data.map(function(val) {
  return val.location_id;
}).join(',');

console.log(result)

我假设您想要一个字符串，因此.join(',')，如果您想要一个数组，只需删除该部分。

Answer 2

您可以在字符串中添加括号，解析字符串（JSON.parse）并映射（Array#map）属性和连接（Array#join）结果。

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var string = '{"name":"Marine Lines","location_id":3},{"name":"Ghatkopar","location_id":2}',
    array = JSON.parse('[' + string + ']'),
    result = array.map(function (a) { return a.location_id; }).join();

console.log(result);

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Answer 3

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obj=[{"name":"Marine Lines","location_id":3}, {"name":"Ghatkopar","location_id":2}]
var res = [];
for (var x  in obj)
if (obj.hasOwnProperty(x))
    res.push(obj[x].location_id);
console.log(res.join(","));

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Answer 4

试试这个

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{{1}}

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Answer 5

var arr = [{"name":"Marine Lines","location_id":3},{"name":"Ghatkopar","location_id":2}];

var location_array = [];
for( var i = 0; i < arr.length; i++ )
{
  location_array.push( arr[i].location_id );
}//for

var location_string = location_array.join(",");
console.log(location_string);

注意：如果arr最初是字符串格式，则可能需要使用JSON.parse（）。

Answer 6

var json = [{"name":"Marine Lines","location_id":3},{"name":"Ghatkopar","location_id":2}];

var locationIds = [];
for(var object in json){
  locationIds.push(json[object].location_id);
}

console.log(locationIds.join(","));

Answer 7

您还可以查看.reduce并手动创建字符串

var d = [{"name":"Marine Lines","location_id":3},{"name":"Ghatkopar","location_id":2}]

var location_id_str = d.reduce(function(p, c) {
  return p ? p + ',' + c.location_id : c.location_id
},'');

console.log(location_id_str)

Answer 8

您可以使用foooof循环

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for..of

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如何使用javascript在逗号分隔的字符串中转换json值

8 个答案: