Question

我想用TapGestureRecognizer实现selector，下面是我将tapGestureRecognizer添加到imageView

的代码

let tapFirstGestureRecognizer = UITapGestureRecognizer(target: self, action: #selector(assignImage(_:)))
firstImageView.isUserInteractionEnabled = true
firstImageView.tag = 1
firstImageView.addGestureRecognizer(tapFirstGestureRecognizer)

这是动作方法

func assignImage(_ sender: UIImageView){
    imagePicker.allowsEditing = false
    imagePicker.sourceType = .photoLibrary
    imageViewTag = sender.tag

    present(imagePicker, animated: true, completion: nil)
}

编译器一直在说

[UITapGestureRecognizer tag]：无法识别的选择器发送到实例0x6080001a7700＆＃39;

Answer 1

问题在于您的方法声明以及为tag的对象分配UIGestureRecognizer。像这样更改方法声明。

func assignImage(_ sender: UITapGestureRecognizer)

或

func assignImage(_ sender: UIGestureRecognizer)

修改：使用UITapGestureRecognizer访问imageView对象。

func assignImage(_ sender: UITapGestureRecognizer) {
    if let imageView = sender.view as? UIImageView {

    }
}

注意：您需要tag与imageView一起设置UITapGestureRecognizer

无法识别的选择器发送到实例Swift 3

1 个答案: