我正在学习Python,并且在试图找出用户数输入的最小值和最大值时,我似乎无法弄明白。
count = 0
x = []
while(True):
x = input('Enter a Number: ')
high = max(x)
low = min(x)
if(x.isdigit()):
count += 1
else:
print("Your Highest Number is: " + high)
print("Your Lowest Number is: " + low)
break
答案 0 :(得分:1)
将程序分解为可管理的小块,只需一个简单的函数即可获得数字
def input_number(prompt="Enter A Number:"):
while True:
try: return int(input(prompt))
except ValueError:
if not input: return None #user is done
else: print("That's not an integer!")
然后编写一个函数来继续从用户那里获取数字,直到输入数字为止
def get_minmax_numbers(prompt="Enter A Number: "):
maxN = None
minN = None
tmp = input_number(prompt)
while tmp is not None: #keep asking until the user enters nothing
maxN = tmp if maxN is None else max(tmp,maxN)
minN = tmp if minN is None else min(tmp,minN)
tmp = input_number(prompt) # get next number
return minN, maxN
然后把它们放在一起
print("Enter Nothing when you are finished!")
min_and_max = get_numbers()
print("You entered Min of {0} and Max of {1}".format(*min_and_max)
答案 1 :(得分:1)
inp=input("enter values seperated by space")
x=[int(x) for x in inp.split(" ")]
print (min(x))
print (max(x))
输出:
Python 3.5.2 (default, Dec 2015, 13:05:11)
[GCC 4.8.2] on linux
enter values seperated by space 20 1 55 90 44
1
90
答案 2 :(得分:0)
x
是一个列表,要将项目附加到列表中,您必须在列表中调用append
方法,而不是直接将项目分配给列表,这将覆盖列表那个项目。
代码:
count = 0
x = []
while(True):
num = input('Enter a Number: ')
if(num.isdigit()):
x.append(int(num))
count += 1
elif(x):
high = max(x)
low = min(x)
print("Your Highest Number is: " + str(high))
print("Your Lowest Number is: " + str(low))
break
else:
print("Please enter some numbers")
break