Question

这可能非常简单，所以原谅我的金发时刻：）

我有一张桌子'专辑'

* albumId
* albumOwnerId (who created)
* albumCSD (create stamp date)

现在我要做的是选择前10个最近更新的专辑。但是，我不希望同一个人的10张专辑回来 - 我只想要每个独特的人一张专辑。来自10个不同的人的10张专辑。

所以，这就是我在下面的内容，但是它无法正常工作，我只是想不出原因。有任何想法吗？

由于

SELECT DISTINCT(albumOwnerId), albumId
FROM album
ORDER BY albumCSD DESC
LIMIT 0,10

以下是一些示例数据，其次是我想要获得的数据。希望这更清楚。

DATA：

albumOwnerID, albumId, albumCSD
18, 194, '2010-10-23 11:02:30'
23, 193, '2010-10-22 11:39:59'
22, 192, '2010-10-12 21:48:16'
21, 181, '2010-10-12 20:34:11'
21, 178, '2010-10-12 20:20:16'
19, 168, '2010-10-12 18:31:55'
18, 167, '2010-10-11 21:06:55'
20, 166, '2010-10-11 21:01:47'
18, 165, '2010-10-11 21:00:32'
20, 164, '2010-10-11 20:50:06'
17, 145, '2010-10-10 18:54:24'
17, 144, '2010-10-10 18:49:28'
17, 143, '2010-10-10 18:48:08'
17, 142, '2010-10-10 18:46:54'
16, 130, '2010-10-10 16:17:57'
16, 129, '2010-10-10 16:17:26'
16, 128, '2010-10-10 16:07:21'
15, 119, '2010-10-10 15:24:28'
15, 118, '2010-10-10 15:24:11'
14, 100, '2010-10-09 18:22:49'
14, 99, '2010-10-09 18:18:46'
11, 98, '2010-10-09 15:50:13'
11, 97, '2010-10-09 15:44:09'
11, 96, '2010-10-09 15:42:28'
11, 95, '2010-10-09 15:37:25'

所需数据：

18, 194, '2010-10-23 11:02:30'
23, 193, '2010-10-22 11:39:59'
22, 192, '2010-10-12 21:48:16'
21, 181, '2010-10-12 20:34:11'
19, 168, '2010-10-12 18:31:55'
17, 145, '2010-10-10 18:54:24'
16, 130, '2010-10-10 16:17:57'
15, 119, '2010-10-10 15:24:28'
14, 100, '2010-10-09 18:22:49'
11, 98, '2010-10-09 15:50:13'

Answer 1

我想通过此查询获得结果

SELECT albumOwnerID, albumId, albumCSD
FROM album
WHERE albumCSD in
(SELECT  Max(album.albumCSD) AS MaxvonalbumCSD
FROM album
GROUP BY album.albumOwnerID);

但是在MS Access中

Answer 2

select albumOwnerID, albumID
from album
Group by albumOwnerID, albumID
Order by albumcsd desc
LIMIT 0,10

编辑：

select albumOwnerID, albumID 
from album
where albumOwnerID in (select distinct albumOwnerID from album order by albumCSD )
LIMIT 0,10

获得MySQL中最顶尖的记录

2 个答案: