Question

我有内联，它显示contenttype模型的数据，因此我会看到content_type和object_id字段而不是真实对象。我可以exclude这些字段 - 这不是问题，但我也希望在下拉列表中将另一个selected作为Places的真实对象。谁能告诉我，我怎么能这样做？

型号：

class Criterias(models.Model):
    name = ...

class Places(models.Model):
    name = ...

class PlacesToCriterias(models.Model):
    content_type = models.ForeignKey(ContentType, on_delete=models.CASCADE)
    object_id = models.PositiveIntegerField()
    content_object = GenericForeignKey()

    criteria_group = models.ForeignKey(Criterias)

管理：

class CriteriaPlacesInlineAdmin(admin.TabularInline):
    model = PlacesToCriterias

class CriteriasAdmin(admin.ModelAdmin):
    inlines = [CriteriaPlacesInlineAdmin]

admin.site.register(Criterias, CriteriasAdmin)

我可以添加CriteriaPlacesInlineAdmin一个form，例如：

class CriteriaPlacesChoicesFieldForm(forms.ModelForm):
    places = forms.ModelChoiceField(PlaceTypesGroups.objects.all(), label='place')

但是如何通过\添加object_id添加到此表单\查询以便选择＆＃39;放在下拉列表中？

Answer 1

找到解决方案。

将表单添加到admin.TabularInline：

class CriteriaPlacesInlineAdmin(admin.TabularInline):
    model = PlacesToCriterias
    form = CriteriaPlacesChoicesFieldForm  # <- ADDED FORM

class CriteriasAdmin(admin.ModelAdmin):
    inlines = [CriteriaPlacesInlineAdmin]

admin.site.register(Criterias, CriteriasAdmin)

形式：

class CriteriaPlacesChoicesFieldForm(forms.ModelForm):
    ct_place_type = ContentType.objects.get_for_model(PlaceTypesGroups)

    object_id = forms.ModelChoiceField(PlaceTypesGroups.objects.all(), label='places')
    content_type = forms.ModelChoiceField(ContentType.objects.all(), initial=ct_place_type, widget=forms.HiddenInput())

    def clean_object_id(self):
        return self.cleaned_data['object_id'].pk

    def clean_content_type(self):
        return self.ct_place_type

如何用admin inline中的实际对象替换content_type和object_id字段？

1 个答案: