Question

我是编程的初学者，我正在制作掷骰子类型的游戏。我想创建一个命令，如果用户键入Exit，整个脚本将打印再见并停止。我试过像：

commandLine = "Exit"

if commandLine == "Exit".
    print ("Bye!")
    quit()

但它根本不起作用。脚本会继续下去。这将是我的剧本：

import random
from random import randint
import re


print ("Welcome to Roll the Dice")

roll = input("Do you want to Roll the Dice? \n Yes / No \n")

if roll == "Yes".lower():
    print("Nice , let`s do it!")

elif roll == "No".lower():
    print("Too bad! :( See you later!")
    quit()

dice = input("Press 'x' to roll the dice!\n")


if dice == "X".lower():
print(random.randint(1,9))

again = input("Sweet ! Would you like to try again?\n")
while again == "Yes".lower():
    dice = input("Press 'x' to roll the dice!\n")

    if dice == "X".lower():
        print(random.randint(1, 9))

    if again == "No".lower():
        print("See you later!")
        quit()

Answer 1

尝试：

while again == "yes":
    dice = input("Press 'x' to roll the dice!\n")

    if dice == "x":
        print(random.randint(1, 9))

    if dice == "no":
        print("See you later!")
        quit()

Answer 2

again = input("Sweet ! Would you like to try again?\n")

while again == "Yes".lower():
    dice = input("Press 'x' to roll the dice!\n")

    if dice == "X".lower():
        print(random.randint(1, 9))

    again = input("Sweet ! Would you like to try again?\n")

if again == "No".lower():
    print("See you later!")
    quit()

这应该解决它！

Answer 3

封锁直到角色终止：

import sys
sys.stdin.read(1)

如果用户输入某些字符，如何停止脚本 - PYTHON

3 个答案: