例如我有一个行数组:
{ "name1", "value1", "other1", "another1" },
{ "name1", "value2", "other2", "another2" },
{ "name2", "value3", "other3", "another3" },
{ "name2", "value4", "other4", "another4" }
我无法生成具有合并单元结构的数组,如:
{ row: 0, col: 0, colspan: 1, rowspan: 2 },
{ row: 2, col: 0, colspan: 1, rowspan: 2 }
其中行是行索引, col 列索引, colspan 是列的范围, rowspan 是桌子上的行数。
到目前为止,我有代码:
var prev;
var entry = {};
var repeat = 1;
var result = [];
for(a in data){
if(a>0){
prev = data[a-1];
for(b in data[a]){
if(prev[b]===data[a][b]){
if(repeat==1){
entry["row"] = a-1;
entry["col"] = b;
entry["colspan"] = 1;
}
repeat++;
}
}
}
}
但是我无法理解何时可以再次rowspan=repeat
然后再repeat=1
entry
,同时我需要将result
推到var cols = data[0].length;
var prev;
var entry = {};
var repeat = [];
for(var i=0;i<cols;i++){
repeat.push(1);
}
var result = [];
for(a in data){
if(a>0){
prev = data[a-1];
for(b in data[a]){
if(prev[b]!=null&&prev[b]===data[a][b]){
if(repeat[b]==1){
entry["row"] = a-1;
entry["col"] = parseInt(b);
entry["colspan"] = 1;
}
repeat[b]++;
}else{
if(repeat[b]>1){
entry["rowspan"] = repeat[b];
result.push(entry);
repeat[b] = 1;
entry = {};
}
}
}
}
}
谢谢大家的帮助!
编辑:我已经设法做了几乎工作的例子,但是没有什么错误,它没有推动最后一次合并...任何想法让它推动最后一个条目?!
Declare @YourTable table ([Event] varchar(100),[Start] DateTime,[End] DateTime, [Tag] varchar(25))
Insert Into @YourTable values
('10PIC700422.PV 10-PSV-700073A 10-PSV-700073B','9/9/16 10:44','9/9/16 10:49','Big'),
('10PIC700422.PV 10-PSV-700073A 10-PSV-700073B','9/9/16 10:50','9/9/16 10:51','Small'),
('11PIC41010.PV 11-PSV-401002A 11-PSV-401002B','4/4/16 12:51','4/4/16 13:58','Big'),
('11PIC41010.PV 11-PSV-401002A 11-PSV-401002B','4/4/16 14:04','4/4/16 14:29','Small'),
('11PIC41010.PV 11-PSV-401002A 11-PSV-401002B','4/4/16 14:51','4/4/16 14:58','Big'),
('11PIC41010.PV 11-PSV-401002A 11-PSV-401002B','4/4/16 15:04','4/4/16 15:29','Small'),
('11PIC41010.PV 11-PSV-401002A 11-PSV-401002B','4-4-16 15:45','4-4-16 15:55','Big'),
('11PIC41010.PV 11-PSV-401002W 11-PSV-401002D','4/4/16 16:04','4/4/16 16:45','Big')
很明显,我的结构有一个减号,因为它使用了prev变量并从第二行开始......但我没有想出任何其他更好的方法。
答案 0 :(得分:0)
所以我想出了我该怎么做:)这是我的代码,以防万一有人需要它。不是最好的方式......但是它有效!
var cols = data[0].length;
var prev;
var entry = {};
var repeat = [];
for(var i=0;i<cols;i++){
repeat.push(1);
}
var result = [];
for(a in data){
if(a>0){
prev = data[a-1];
for(b in data[a]){
if(prev[b]!=null&&prev[b]===data[a][b]){
if(repeat[b]==1){
entry["row"] = a-1;
entry["col"] = parseInt(b);
entry["colspan"] = 1;
}
repeat[b]++;
}else{
if(repeat[b]>1){
entry["rowspan"] = repeat[b];
result.push(entry);
repeat[b] = 1;
entry = {};
}
}
}
if(a==data.length-1){
for(var i=0;i<repeat.length;i++){
if(repeat[i]>1){
entry["rowspan"] = repeat[i];
result.push(entry);
repeat[i] = 1;
entry = {};
}
}
}
}
}