Question

Table 1

S_no Name Attempt Score Status 
1     sam    1      25    Fail
2     sam    2      45    Pass
3     sam    3       12   Fail
4     Dante   1      56   Pass
5     Dante   2      78   Pass
6     jill    1      16   Fail
7     Jack    1       90  Pass

In the Above table . number of student passed = 2 and number od student Failed = 2.

status of the Final Attempt is taken in to Consideration .

I want to Show

Id Passed_no failed_no 
1    2         2

Answer 1

您可以使用ROW_NUMBER()和条件聚合：

SELECT COUNT(CASE WHEN s.status = 'Pass' THEN 1 END) as Passed_no,
       COUNT(CASE WHEN s.status = 'Fail' THEN 1 END) as Failed_no
FROM (
    SELECT t.*,
           ROW_NUMBER() OVER(PARTITION BY t.name ORDER BY t.attempt DESC) as rnk
    FROM YourTable t) s
WHERE s.rnk = 1

Answer 2

您可以使用PIVOT获得结果：

SELECT *
FROM (
      SELECT NAME ,CASE SUM(CASE WHEN STATUS='Pass' THEN 0 ELSE 1 END) 
                      WHEN  0 THEN 'PASS' 
                      ELSE 'FAIL' 
                   END STATUS
      FROM TABLE_NAME
      GROUP BY NAME)
PIVOT (COUNT(NAME) FOR STATUS IN ('PASS' AS "Passed_no" ,'FAIL' AS "Failed_no"));

Aggregation in Column level display

2 个答案: