Question

排序问题

a = raw_input("Do you know the number of inputs ?(y/n)")    
if a == 'y':    
   n = int(input("Enter the number of inputs : "))    
   total = 0    
   i = 1    
  while i <= n:     
   s = input()    
   total = total + int(s)    
   i = i + 1    
   s.sort()    
   print s     
   print('The sum is ' + str(total))

Answer 1

n = int(input("Enter the number of inputs : "))
total = 0
i = 1
array = []
while i <= n:
    s = int(input())
    array.append(s)
    total = total + int(s)
    i = i + 1
array.sort()
print(array) 
print('The sum is ' + str(total))

这将解决您的问题，排序适用于列表而不是str对象

Answer 2

因为您在输入时尝试sort。 sort仅适用于迭代列表和元组。

我只是重写你的代码，

a = raw_input("Do you know the number of inputs ?(y/n)")
if a == 'y':
    n = int(input("Enter the number of inputs : "))
    inputs = [] 
    for i in range(n):
        s = input()
        inputs.append(int(s))
    inputs.sort()

    print inputs 
    print('The sum is ',sum(inputs))

<强> 修改

只需将整个操作更改为一个函数，并在while循环中输入yes / no question，并从程序中退出错误的输入。

def foo():
    n = int(input("Enter the number of inputs : "))
    inputs = [] 
    for i in range(n):
        s = input()
        inputs.append(int(s))
    inputs.sort()

    print inputs 
    print('The sum is ',sum(inputs))

while True:
    a = raw_input("Do you know the number of inputs ?(y/n)")    
    if a == 'y':
        foo()       
    elif a == 'n':
        print 'We are giving one more option.'      
        continue
    else:
        print 'Wrong entry'
        break

Answer 3

将数字存储在列表中。然后使用sum（list）获取列表中元素的总和，并排序（list）以获得按升序排序的列表。

    n = int(input("Enter the number of inputs: "))

    l=[]

    for i in range(n):

        s = input()

        l.append(int(s))

    print('The sum is', sum(l))

    print('Sorted values', sorted(l))

你在找这个吗？

我无法从输入中获取排序值

3 个答案: