调用Void方法将整数打印为文本

时间:2016-10-13 03:19:18

标签: java methods invoke void

我很担心放在oneDigit方法的参数中的内容以及在我调用oneDigit method的主方法中放入什么以打印出四位数的整数4321单词(四三二)。任何帮助将不胜感激!

import javax.swing.JOptionPane;

public class ToEnglish {

   public static void oneDigit(int n1, int n2, int n3, int n4){

   }//end oneDigit

    public static void main(String[] args) {

      int number;
      int n1;
      int n2;
      int n3;
      int n4;
      String input;

      JOptionPane.showMessageDialog(null,
                                   "Welcome to the ToEnglish program by Josh Higgins!",
                                   "ToEnglish",
                                   JOptionPane.PLAIN_MESSAGE);
      input = JOptionPane.showInputDialog(null,
                                               "Please enter a four-digit integer",
                                               "ToEnglish",
                                               JOptionPane.QUESTION_MESSAGE);
      number = Integer.parseInt(input);

      //breaking integer up into 4 digits
      n1 = number / 1000;
      int n1Remainder = number % 1000;
      n2 = n1Remainder / 100;
      int n2Remainder = number % 100;
      n3 = n2Remainder / 10;
      int n3Remainder = number % 10;
      n4 = number % 10;

      if
      (number < 0000 || number > 9999) { 
         System.out.println("Invalid input");
      }
      else {
      n1 = number / 1000;
      n1Remainder = number % 1000;
      n2 = n1Remainder / 100;
      n2Remainder = number % 100;
      n3 = n2Remainder / 10;
      n3Remainder = number % 10;
      n4 = number % 10;
      }

      if ((number > 0000) && (number < 9999)) {
      System.out.println(n1 + " " + n2 + " " + n3 + " " + n4 + " ");
      }
      else {
      System.out.println("Invalid input");
      }

      //invoking oneDigit Method in order to print the four digit integer in text
      oneDigit(n1);
      oneDigit(n2);
      oneDigit(n3);
      oneDigit(n4);

 System.out.println("All done for now!");
      System.exit(0);

   }//end of the main method

}//end of the class

@Vishal,这是我改进的代码,但是当我运行它时,我只得到4 3 2 1,而不是文本。有什么建议吗?

import javax.swing.JOptionPane;

public class ToEnglish {

   public void oneDigit(int digit){

   }//end oneDigit

    public static void main(String[] args) {

      int digit=0;
      int number;
      int n1;
      int n2;
      int n3;
      int n4;
      String input;

      JOptionPane.showMessageDialog(null,
                                   "Welcome to the ToEnglish program by Josh Higgins!",
                                   "ToEnglish",
                                   JOptionPane.PLAIN_MESSAGE);
      input = JOptionPane.showInputDialog(null,
                                               "Please enter a four-digit integer",
                                               "ToEnglish",
                                               JOptionPane.QUESTION_MESSAGE);
      number = Integer.parseInt(input);

      //breaking integer up into 4 digits
      n1 = number / 1000;
      int n1Remainder = number % 1000;
      n2 = n1Remainder / 100;
      int n2Remainder = number % 100;
      n3 = n2Remainder / 10;
      int n3Remainder = number % 10;
      n4 = number % 10;

      if
      (number < 0000 || number > 9999) { 
         System.out.println("Invalid input");
      }
      else {
      n1 = number / 1000;
      n1Remainder = number % 1000;
      n2 = n1Remainder / 100;
      n2Remainder = number % 100;
      n3 = n2Remainder / 10;
      n3Remainder = number % 10;
      n4 = number % 10;
      }

      if ((number > 0000) && (number < 9999)) {
      System.out.println(n1 + " " + n2 + " " + n3 + " " + n4 + " ");
      }
      else {
      System.out.println("Invalid input");
      }

      switch (digit) {
         case 1 : System.out.print("One");
         break;
         case 2 : System.out.print("Two");
         break;
         case 3 : System.out.print("Three");
         break;
         case 4 : System.out.print("Four");
         break;
         case 5 : System.out.print("Five");
         break;
         case 6 : System.out.print("Six");
         break;
         case 7 : System.out.print("Seven");
         break;
         case 8 : System.out.print("Eight");
         break;
         case 9 : System.out.print("Nine");
         break;
       }

 System.out.println("All done for now!");
      System.exit(0);

   }//end of the main method

}//end of the class

2 个答案:

答案 0 :(得分:0)

根据您的方法原型,oneDigit方法接受四个整数,并且您只使用一个整数调用该方法。 您可以使用一个参数编写方法。在方法内部使用带有参数的开关盒来打印单词中的数字。

例如: 此代码应写在oneDigit方法

{{1}}

你可以跟随所有数字。

或者您可以编写一个if-else if块来检查传递给方法的整数,并在该块中的单词中打印数字。

编辑:代码块

答案 1 :(得分:-1)

试试这个:

public static String oneDigit(int digit){
  switch(digit){
    case 0:
    return "zero";
    case 1:
    return "one";
    //add missing cases
    default:
    return "not in range"; //you can throw an exception here if you prefer
  }
}