Question

根据4J41的提议（感谢他/她），我将previous question分成了一个新的。

我的mongoDB查询最后一个问题。我很乐意得到一些帮助...

在我的MongoCollection下面： 请注意，KLLS可以是a，b或c，还有3 types：processus，work，{ {1}}，对某些人来说，viewing {仅适用于key）。

work

目前，查询是（再次感谢4J41用户）：

{_id: 1, KLLS: "a", action: "A", type: "Processus", date: Date }
{_id: 2, KLLS: "b", action: "B", type: "Processus", date: Date }
{_id: 5, KLLS: "a", action: "E", type: "Viewing"  , date: Date }
{_id: 6, KLLS: "b", action: "F", type: "Viewing"  , date: Date }
...
{_id: 3, KLLS: "a", action: "AB", type: "Work", date: Date, key:"123" }
{_id: 4, KLLS: "b", action: "XY", type: "Work", date: Date, key: "123" }
{_id: 3, KLLS: "a", action: "AB", type: "Work", date: Date, key:"456" }
{_id: 4, KLLS: "b", action: "XY", type: "Work", date: Date, key: "456" }
...

我在这里修改了一些订单/措辞以使其更清晰

此时我得到了：

db.collection('events').aggregate([
   { $match: { KLLS: {$in: something} } },
   { $sort: { date: 1 } },
   { '$group': {
     '_id': '$KLLS',
     'Processus': {'$push': {'$cond': [{'$eq': ['$type', 'Processus']}, '$$ROOT', false]}},
     'Works': {'$push': {'$cond': [{'$eq': ['$type', 'Works']}, '$$ROOT', false]}},
     'Viewings': {'$push': {'$cond': [{'$eq': ['$type', 'Viewings']}, '$$ROOT', false]}},
     'Details': {'$push': {'$cond': [{'$eq': ['$action', 'Stuff']}, '$$ROOT', false]}}
          }},
    {'$project': {
      '_id': 0,
      'KLLS': '$_id',
      'Processus': { '$setDifference': ['$Processus', [false]] },
      'Works': { '$setDifference': ['$Works', [false]] },
      'Viewings': { '$setDifference': ['$Viewings', [false]] },
      'Details': { '$setDifference': ['$Details', [false]] }
          }}
        ]
      )

唯一的最后一个问题是[ { _id: { KLLS: 'a'}, Processus: [ everything is ok ] Viewing: [ everything is ok ] Details: [ everything is ok ] Work: [ {_id: 3, KLLS: "a", action: "AB", type: "Work", date: Date, key:"123" } {_id: 4, KLLS: "b", action: "XY", type: "Work", date: Date, key: "123" } {_id: 5, KLLS: "a", action: "AB", type: "Work", date: Date, key:"456" } {_id: 6, KLLS: "b", action: "XY", type: "Work", date: Date, key: "456" } ] }] ...。目前，我有一个由Work条记录组成的列表（4：_id，3，4，5）。往上看。 我希望6下面的小组如下（警告：我不知道key的{{1}}。

value

我尝试过（1）一种嵌套的key和（2）将条件添加到第一个$ group中以制作复合[ { _id: { KLLS: 'a'}, Processus: [ everything is ok ] Viewing: [ everything is ok ] Details: [ everything is ok ] Work: [ [ // this a "$group" by key {_id: ..., KLLS: "...", action: "...", type: "Work", date: Date, key:"123" } {_id: ..., KLLS: "...", action: "...", type: "Work", date: Date, key: "123" } ] [ // this a "$group" by key {_id: ..., KLLS: "...", action: "...", type: "Work", date:..., key:"456" } {_id: ..., KLLS: "...", action: "...", type: "Work", date:..., key: "456" } ] ] ...，但它似乎不起作用（空）查询结果）。

你知道如何解决这个问题吗？感谢。

Answer 1

您可以添加嵌套的$cond来过滤键123或456.然后，最后的$project阶段可用于构建数组。

db.events.aggregate([
    {"$group":
        {   "_id":"$KLLS",
            "Processus":{"$push":{"$cond":[{"$eq":["$type","Processus"]},'$$ROOT',false]}},
            "Work123":
                {"$push":
                    {"$cond":
                        [
                            {"$eq":["$type","Work"]},
                            {"$cond":
                                [
                                    {"$eq":["$key","123"]},
                                    '$$ROOT',
                                    false
                                ]
                            },
                            false
                        ]
                    }
                },
            "Work456":
                {"$push":
                    {"$cond":
                        [
                            {"$eq":["$type","Work"]},
                            {"$cond":
                                [
                                    {"$eq":["$key","456"]},
                                    '$$ROOT',
                                    false
                                ]
                            },
                            false
                        ]
                    }
                },
            "Viewing":{"$push":{"$cond":[{"$eq":["$type","Viewing"]},'$$ROOT',false]}}
        }
    },
    {"$project": { "_id":0, "KLLS":"$_id", "Processus":{"$setDifference":["$Processus",[false]]},
        "123":{"$setDifference":["$Work123",[false]]},
        "456":{"$setDifference":["$Work456",[false]]},
        "Viewing":{"$setDifference":["$Viewing",[false]]}
        }
    },
    {"$project": { "KLLS":1, "Processus":1, "Work" : [{"123" : "$123"}, {"456" : "$456"}],"Viewing":1}}
])

Mongodb - $ group内的$ group（按'key'）

1 个答案: