Question

任何人都可以帮我吗？我只想使用javascript打印模式打印此表。但是怎么样？还使用Web样式中的打印视图。我非常感谢任何帮助。先感谢您。 :)

这是我的代码。

<?php
  if(isset($_POST['search'])) {
    $valueToSearch = $_POST['valueToSearch'];
    $query = "SELECT * FROM dailytimerecord WHERE CONCAT(Dtrec_ID, TimeIn, TimeOut) LIKE '%".$valueToSearch."%'";
    $search_result = filterTable($query);
  } else {
    $query = "SELECT * FROM dailytimerecord";
    $search_result = filterTable($query);
  }
  function filterTable($query) {
    $connect = mysqli_connect("localhost", "root", "", "alqdb");
    $filter_Result = mysqli_query($connect, $query);
    return $filter_Result;
  }
?>
<!DOCTYPE html>
<html>
  <head>
    <title>PHP HTML TABLE DATA SEARCH</title>
    <style>
      table,tr,th,td {
        border: 1px solid black;
      }
    </style>
  </head>
<body>
<form method="post">
  <input type="text" name="valueToSearch" placeholder="Value To Search"><br><br>
  <input type="submit" name="search" value="Filter"><br><br>
  <input type="button" name="print" value="Print"><br><br>
  <table>
    <tr>
      <th>Name</th>
      <th>Dtrec_ID</th>
      <th>Date</th>
      <th>Time In</th>
      <th>Time Out</th>
    </tr>
    <?php while($row = mysqli_fetch_array($search_result)):?>
    <tr>
      <td></td>
      <td><?php echo $row['Dtrec_ID'];?></td>
      <td><?php echo date("F j, Y", strtotime($row['TimeIn']));?></td>
      <td><?php echo date("h:i, A", strtotime($row['TimeIn']))?></td>
      <td><?php echo date("h:i, A", strtotime($row['TimeOut']));?></td>
    </tr>
    <?php endwhile;?>
  </table>
</form>
</body>
</html>

使用javascript打印我的表

0 个答案: