我在我的ASP.NET MVC项目中跟随了jQuery Datatable - Sliding child rows示例(只看了#34;完整代码"该页面上的部分),我可以列出master&静态细节数据正确。但是,当我想通过AJAX动态检索细节数据时,由于错误 TypeError:table.fnOpen不是函数,我无法正确列出它们。有一个解决方案将 D ataTable更改为 d ataTable,但在这种情况下我遇到了其他错误。问题恰恰在于点击和放大格式方法,我认为我犯了一些错误的定义。你能不能看看并澄清我的错误在哪里?提前谢谢......
function format(d) {
return '<div class="slider">' +
'<table style="width:100%">' +
'<tr>' +
'<th>Name</th>' +
'<th>Surname</th> ' +
'<th>Number</th>' +
'</tr>' +
'<tr>' +
'<td>' + d.StudentName + '</td>' +
'<td>' + d.StudentSurname + '</td> ' +
'<td>' + d.StudentNumber + '</td>' +
'</tr>' +
'</table>'
'</div>';
}
$(document).ready(function () {
var table;
table = $('#dtbLabGroup')
.DataTable(
//code omitted for brevity
"columns": [
{
"class": 'details-control',
"orderable": false,
"data": null,
"defaultContent": ''
},
{ "name": "Lab" },
{ "name": "Schedule" },
{ "name": "Term" },
{ "name": "Status" }
],
"order": [[1, 'asc']],
});
// Add event listener for opening and closing details
$('#dtbLabGroup tbody').on('click', 'td.details-control', function () {
// !!! There might be a problem regarding to these 3 parameters
var tr = $(this).closest('tr');
var row = table.row(tr);
var nTr = $(this).parents('tr')[0];
//
if (row.child.isShown()) {
// This row is already open - close it
$('div.slider', row.child()).slideUp(function () {
row.child.hide();
tr.removeClass('shown');
});
}
else {
// Open this row
row.child(format(row.data()), 'no-padding').show();
tr.addClass('shown');
$('div.slider', row.child()).slideDown();
// !!! There is PROBABLY a problem
// !!! I added the following code for retrieving data via AJAX call.
var id = 8; //used static id for testing
$.get("GetStudents?id=" + id, function (students) {
table.fnOpen(nTr, students, 'details');
});
}
});
});
更新I:以下是修改后的format()方法:
function format(d) {
var htmlResult = '<div class="slider">' +
'<table style="width:100%">' +
'<tr>' +
'<th>Name</th>' +
'<th>Surname</th> ' +
'<th>Number</th>' +
'</tr>';
$.each(d, function (i, d) {
htmlResult += '<tr><td>' + d[i].StudentName + '</td><td>' + d[i].StudentSurname + '</td><td>' + d[i].StudentNumber + '</td></tr>';
});
htmlResult += '</table>' +
'</div>';
return htmlResult;
}
答案 0 :(得分:2)
您需要在子行中显示加载指示符,通过Ajax检索内容并将其注入替换加载指示符的子行。
例如:
// ... skipped ...
// Open this row
row.child('<p><center>Loading...</center></p>', 'no-padding' ).show();
tr.addClass('shown');
$('div.slider', row.child()).slideDown();
$.getJSON("GetStudents?id=" + id, function(data){
$('td', row.child()).html(format(data));
$('div.slider', row.child()).show();
});
// ... skipped ...
请参阅this example以获取代码和演示。