Question

我正在尝试使用mysqli_query

在数据库中显示数据

但是当我想显示order by title时，会显示以下内容

'order clause'中的未知列'title'

删除order by title后，就可以了

上下文代码

<?php
    include "database_conn.php";

    $sqlEvent = "SELECT * FROM te_events ORDER BY title"; //the problem is here

    //query the statement
    $event= mysqli_query ($conn , $sqlEvent)
    or die (mysqli_error($conn));

?>

<!DOCTYPE html>
<html lang="en">
<head>
<title> Select Event </title>
<meta charset="utf-8">
</head>
<body>

<h1>Select Event</h1>

<table border = "1">

<thead>
    <th>Title</th>
</thead>

<?php

    //display all the event record
    while ($row = mysqli_fetch_assoc ($event)){
        //extract the field
        $id    = $row["eventID"];
        $title = $row["eventTitle"];

        //start a row
        echo"<tr>\n";

        //output the URL
        echo "<td>\n";
        echo "<div> <a href = \"viewEventDetails.php?eventTitle=$title\">
                    $title</a>\n";
        echo "</td>\n";
    }

?>
</table>
</body>
</html>

<?php
    mysqli_close($conn);
?>

有关如何按标题显示数据的任何建议将不胜感激。

Answer 1

从title替换为eventTitle，因为您的$行表示

$sqlEvent = "SELECT * FROM te_events ORDER BY eventTitle"; //

Answer 2

查看处理结果集的代码我会说如果你改变了这个

$sqlEvent = "SELECT * FROM te_events ORDER BY title";

到此

$sqlEvent = "SELECT * FROM te_events ORDER BY eventTitle";

它可能会起作用

Answer 3

修改

将行更改为：

$sqlEvent = "SELECT * FROM te_events ORDER BY eventTitle";

ORDER BY之后的单词需要是数据库te_events表中的字段。

根据你所说的$title = $row["eventTitle"];后面的陈述来判断，eventTitle是你在ORDER BY条款中使用的内容。

Answer 4

试试这个$sqlEvent = "SELECT * FROM te_events ORDER BY eventTitle";

Answer 5

将标题替换为eventTitle，这是您的错误，实际的列名是eventTitle

$title = $row["eventTitle"];

$sqlEvent = "SELECT * FROM te_events ORDER BY eventTitle";

'order clause'中的未知列'title'

5 个答案: