c＃Regular Expression：打印与模式不同的字符串

Question

我正在尝试使用正则表达式，我有以下字符串：

M3A4S0S3I2M1O4
M3a4s0s3i2m1o4   
m3a4s0s3i2m1o4
F3a4i0l4l1a6
30470041106042700156
30470031201042506146

字符串模式为string pattern = @"\D";，我想要打印：

M3A4S0S3I2M1O4
M3a4s0s3i2m1o4
m3a4s0s3i2m1o4
F3a4i0l4l1a6

因为它在此字符串中找到匹配项。我不打印30470041106042700156 30470031201042506146，因为它找不到任何匹配项。 我写了代码：

using System;
using System.Text.RegularExpressions;

public class Example
{
    public static void Main()
    {
        string pattern = @"\D";
        string input = @"M3A4S0S3I2M1O4 M3a4s0s3i2m1o4 m3a4s0s3i2m1o4    F3a4i0l4l1a6 30470041106042700156 30470031201042506146";

但我不知道怎么能完成它。我该如何解决？

Answer 1

using System;
using System.Text.RegularExpressions;

public class Program {
    public static void Main() {
        string[] input = { "M3A4S0S3I2M1O4", "M3a4s0s3i2m1o4", "m3a4s0s3i2m1o4", "F3a4i0l4l1a6", "30470041106042700156", "30470031201042506146" };
        foreach (var line in input)
            if (Regex.IsMatch(line, @"\D"))
                Console.WriteLine(line);
    }
}

<强>输出

M3A4S0S3I2M1O4
M3a4s0s3i2m1o4
m3a4s0s3i2m1o4
F3a4i0l4l1a6

Answer 2

实际上你不需要正则表达式，使用简单的拆分，连接和LINQ：

string input = @"M3A4S0S3I2M1O4
M3a4s0s3i2m1o4
m3a4s0s3i2m1o4
F3a4i0l4l1a6
30470041106042700156
30470031201042506146";
string res = string.Join("\r\n", input.Split(new[] {"\r\n"}, StringSplitOptions.None)
       .Where(line => !line.All(Char.IsDigit))
       .ToArray());

.Where(line => !line.All(Char.IsDigit))部分仅保留非全数字的行。

如果您有一个字符串列表，请将string.Join("\r\n", input.Split(new[] {"\r\n"}, StringSplitOptions.None)替换为您的列表变量并省略string.Join。