如何从XSD获取XmlSchema对象，这是C＃中的字符串？

Question

如何从包含所有XSD内容的大字符串中获取XmlSchema对象？

Answer 1

Read方法是静态的。所以最好使用

XmlSchema schema = XmlSchema.Read(
    schemaReader, (sender, args) =>
    {
         // HANDLE VALIDATION FAILED
    });                                                                        

Answer 2

您可以使用StringReader：

string content = ".......";
XmlSchema schema = new XmlSchema();
schema.Read(new StringReader(content), ValidateSchema);

Answer 3

string xsdContent = "...";
string xmlContent = "...";

XmlSchemaSet schema;
XDocument xmlDoc;
using (var ms = new MemoryStream(Encoding.UTF8.GetBytes(xsdContent)))
{
    var xsc = XmlSchema.Read(ms, (o, e) =>
    {
        Error.SetWarning($"XML Schema error: {e.Message}");
    });
    schema = new XmlSchemaSet();
    schema.Add(xsc);
    xmlDoc = XDocument.Parse(xmlContent, LoadOptions.SetLineInfo);
}

xmlDoc.Validate(schema, (o, e) =>
{
    // handle validation errors
});