Question

$ arr1适用于所有值。这里checked=false。

$arr1 = [{"event_id":"2","name":"I have a new message","checked":"false"},{"event_id":"3","name":"A meeting awaits
     me","checked":"false"},{"event_id":"4","name":"Someone visited my profil","checked":"false"},{"event_id"
    :"5","name":"Someone like my profile","checked":"false"},{"event_id":"6","name":"My picture was approved"
    ,"checked":"false"},{"event_id":"7","name":"My picture was rejected","checked":"false"},{"event_id":"8"
    ,"name":"VIP purchase confirmation","checked":"false"}];

$ arr2仅用于检查值。这里checked=true。

$arr2 = [{"event_id":"2","name":"I have a new message","checked":"true"},{"event_id":"3","name":"A meeting awaits
     me","checked":"true"},{"event_id":"4","name":"Someone visited my profil","checked":"true"},{"event_id"
    :"5","name":"Someone like my profile","checked":"true"},{"event_id":"7","name":"My picture was rejected"
    ,"checked":"true"},{"event_id":"8","name":"VIP purchase confirmation","checked":"true"}]

现在我想要一个如下所示的数组，其中“checked”：“false”和“checked”：“true”两者都在那里。怎么可能？

$arr3 = [{"event_id":"2","name":"I have a new message","checked":"true"},{"event_id":"3","name":"A meeting awaits
     me","checked":"true"},{"event_id":"4","name":"Someone visited my profil","checked":"true"},{"event_id"
    :"5","name":"Someone like my profile","checked":"true"},{"event_id":"6","name":"My picture was approved"
    ,"checked":"false"},{"event_id":"7","name":"My picture was rejected","checked":"true"},{"event_id":"8"
    ,"name":"VIP purchase confirmation","checked":"true"}];

Answer 1

你的问题必须是这样的： MERGE JSON OBJECTS

按照以下步骤，将b加入a要容易得多。

您需要为json_objects和single array

json_decode()

然后在执行$arr1后，您需要使用$arr2，因为json_decode()之后您的数据将为array_merge()，因此您可以合并两个数组。< / LI>
如果您需要再次输出json_decode()，则需要执行最后一步，您需要为array()

json_object()

您的场景示例

json_encode()

<强>输出：

给定JSON字符串

array_merge()

合并后的JSON：

<?php
$json_first = '{
    "id": "#001",
    "username": "Name One",
    "type": "ADMIN",
    "status": "ACTIVE"   
}';

$json_second =  '{
    "id": "#002",
    "username": "Name Two",
    "type": "USER",
    "status": "INACTIVE"
}';
$user_info[] = json_decode($json_first,TRUE);
$user_info[] = json_decode($json_second,TRUE);
$json_merge = json_encode($user_info);
?>

<h4>Given JSON String:</h4> 
<p>
<div>$json1 = <?php echo $json1; ?></div>
<div>$json2 = <?php echo $json2; ?></div>
</p>
<h4>Output:</h4> 
<div><?php echo $json_merge; ?></div>

删除重复 ARRAY MERGE 。

如果您需要合并数组并删除重复值，则可以选择{"id": "#001", "username": "Name One", "type": "ADMIN", "status": "ACTIVE" } {"id": "#002", "username": "Name Two", "type": "USER","status": "INACTIVE" }函数。

这将删除所有副本，然后您可以执行您需要的操作。

[{"id": "#001", "username": "Name One", "type": "ADMIN", "status": "ACTIVE" },{"id": "#002", "username": "Name Two", "type": "USER","status": "INACTIVE" }]

参考：http://php.net/manual/en/function.array-unique.php

数组在php

1 个答案:

您的场景示例