Question

我正在尝试解析JSON对象时遇到SQL异常。这是我的代码片段。

public JSONArray paymentMode(String stringObjects) throws SQLException {

    JSONObject jsonObject = JSONFactoryUtil.createJSONObject();

    //JSONOBJECT RETURN
    JSONObject jsonObjectReturn =  JSONFactoryUtil.createJSONObject();
    JSONObject obj = JSONFactoryUtil.createJSONObject();
    JSONArray array = JSONFactoryUtil.createJSONArray();
    Session session = null;
    Connection conn = null;
    CallableStatement callableStatement = null;
    try {
        // test
        BeanLocator beanLocator = PortletBeanLocatorUtil
                .getBeanLocator("Mrcos-services-portlet");
        BasicDataSource bds = (BasicDataSource) beanLocator
                .locate("mrcosDataSourceTarget");
        conn = (Connection) bds.getConnection();

        jsonObject = JSONFactoryUtil.createJSONObject(stringObjects);

        JSONArray jsonArray = jsonObject.getJSONArray("dataArray");


        for (int i = 0; i < jsonArray.length(); i++) {
            obj = jsonArray.getJSONObject(i);



        callableStatement = (CallableStatement) conn
                .prepareCall("{call PaymentModeSPv2(?,?,?,?,?,?,?,?,?,?,?,?,?)}");
        callableStatement.setString(1, jsonObject.getString("mode"));
        callableStatement.setString(2, jsonObject.getString("num1"));
        callableStatement.setString(3, jsonObject.getString("date1"));
        callableStatement.setString(4, jsonObject.getString("num2"));
        callableStatement.setString(5, jsonObject.getString("date2"));
        callableStatement.setString(6, jsonObject.getString("remarks"));
        callableStatement.setDouble(7, jsonObject.getDouble("amount"));
        callableStatement.setString(8, jsonObject.getString("receipt"));
        callableStatement.setString(9, jsonObject.getString("algo"));
        callableStatement.setString(10, jsonObject.getString("code"));
        callableStatement.setString(11, jsonObject.getString("address"));
        callableStatement.setString(12, jsonObject.getString("status"));
        callableStatement.registerOutParameter(13, Types.INTEGER);

        callableStatement.executeQuery();

        String xreturn = callableStatement.getString(13);



        jsonObjectReturn =  JSONFactoryUtil.createJSONObject();
        jsonObjectReturn.put("xreturn", xreturn);

        array.put(jsonObjectReturn);    


        System.out.println("jsonObjectReturn : " + jsonObjectReturn);

        }
        return array;

    } catch (Exception e) {
        e.printStackTrace();
    } finally {
        if (callableStatement != null) {
            callableStatement.close();
        }

        if (conn != null) {
            conn.close();
        }
        closeSession(session);
    }

    jsonObjectReturn =  JSONFactoryUtil.createJSONObject();
    jsonObjectReturn.put("result", "NO RESULTS FOUND!");
    return array;

}

我在 callableStatement.setDouble（7，jsonObject.getDouble（“amount”））时遇到错误; 说 java.sql.SQLException：'NaN'不是有效的数字或近似数值。

金额在我的数据库中是十进制的。我也尝试使用float而不是double但仍然提供相同的错误消息。我也尝试传递一个整数和一个十进制数，但仍然发生相同的错误。请帮助我暂时停留一段时间。谢谢！

Answer 1

您在javascript中收到了[NaN][1] jsonObject.getDouble("amount")。所以你需要以某种方式处理它。例如。您可以将其替换为0或Double.NaN：

String amt = jsonObject.getString("amount");
Double amount = "NaN".equals(amt) ? Double.NaN : Double.parseDouble(amt);
callableStatement.setDouble(7, amount);

获取SQL异常“NaN”不是有效的数字或近似数值

1 个答案: