Question

我想拆分列表项，然后为它们添加值。要做到这一点，我需要采取第一句话;将其拆分为一个列表;使用isdigit()确定列表元素是否为数字，然后将1添加到元素;使用join()将新列表元素连接在一起。它需要使用带枚举的for循环来完成。

这是我的代码：

a="You would like to visit "+li[0]+" as city 1 and " +li[1]+ " as city 2 and "+li[2]+" as city 3 on your trip"      
print a
printer = a.split(" ")
print printer
if printer.isdigit():

Answer 1

看起来你想要这样的东西
我已将li[0]和其他变量替换为字符串＆＃34; Some_Value＆＃34;因为我不知道那些变量的价值

a="You would like to visit " + "Some_Value" +" as city 1 and " + "Some_Value" + " as city 2 and "+ "Some_Value" + " as city 3 on your trip"
a = a.split(" ")
index = 0

for word in a:
    if word.isdigit():
        a[index] = str(int(word) + 1)
    index += 1
print " ".join(a)

<强> OP
You would like to visit Some_Value as city 2 and Some_Value as city 3 and Some_Value as city 4 on your trip

Answer 2

这是另一种查看解决方案（添加了评论）

的方法

li = ["New York", "London", "Tokyo"] #This is an example list for li

a="You would like to visit "+li[0]+" as city 1 and " +li[1]+ " as city 2 and "+li[2]+" as city 3 on your trip"      
print a
printer = a.split(" ")
print printer

new_printer = []
for word in printer:
    if word.isdigit():
        word = str(int(word) + 1) #this increments word by 1. first we have to convert the string value of word to number (int) and then add one (+ 1), and then convert it back to a string (str) and save it back to word
    new_printer.append(word) # this adds word (changed or not) at the end of new_printer
end_result = " ".join(new_printer) #this joins all the words in new_printer and places a space between them

print end_result

Answer 3

' '.join([ str( int(i)+1 ) if i.isdigit() else i for i in a.split() ] )

拆分列表项并在python

3 个答案: