Question

我从字段中捕获数据并将其存储为

data.append(newdata)

然后将每个完整记录存储为：

list_of_rows.append(data)

我然后尝试保存到csv

data_mod = [[item] for item in list_of_rows]

with open("./hotels.csv", "wb") as outfile:
    writer = csv.writer(outfile)
    for row in data_mod:
        writer.writerow(row)
outfile.close()

但是当我将它加载到csv中时，所有内容都会保存到第一个字段中。如何正确分解？

修改

每行看起来像

[[u'Staybridge Suites London - Vauxhall', '\nTushar K\n', '\nIlford\n', 0, u'2 reviews', '5 of 5 stars', '29 September 2016', u'\nHome comes at staybridge........it nice with stay bridge.....awesome ambiance, kitchen, rooms, break fast area.............\nEverything is at place.....\nTalking about people of stay bridge... they all are very much cooperative, kind, best service people I have ever saw, meet...... its absolutely fantastic with stay bridge..........love u guysss.....\n']]

Answer 1

不要将行包装在列表中，您已经有了列表列表。您还需要去除换行符，或者每行都将获得它自己的行，而不是将所有行写入一行并编码为utf-8：

with open("./hotels.csv", "w") as outfile:
    writer = csv.writer(outfile)
    writer.writerows([s.strip().encode("utf-8") if isinstance(s, unicode) else s
                     for s in row] for row in list_of_rows)

beautifulsoup出口到csv

1 个答案: