Question

我有两个名为'travel_request'和'status'的表。我有状态值。基于该值我想获取状态表'id'并想要在同一个控制器中更新“travel_request”表status_id。如果我的状态值为'waiting'，我想从状态表中取出id = 1并需要将其插入到travel_request表中

状态表-id，状态 travel_request-ID，STATUS_ID

public function statusUpdate(Request $request)
{
  $request_data = $request->all();
   $id = $request_data['id'];   
   $status=$request_data['status'];  //waiting(1),approved(2), 
  DB::table('travel_request')
        ->where('id',$id )
        ->update(['status_id' => $status]); 
  return response()->json();        
}

Answer 1

你的意思是这样的：

public function statusUpdate(Request $request)
{
  $request_data = $request->all();
   $id = $request_data['id'];   
   $status=$request_data['status'];  //waiting(1),approved(2), 
  DB::table('travel_request')
        ->where('id',$id )
        ->update(['status_id' => DB::table('status')->where('COLUMN_NAME', $status)->first()->id]); 
  return response()->json();        
}

Answer 2

使用Eloquent：

public function statusUpdate(Request $request)
{
    $status_id = Status::where('status', $request->status)->first()->id;
    TravelRequest::where('id', $request->id)->update(compact('status_id'));
    return response()->json();        
}

另一种方法是在配置文件中保留状态，例如：

status => [
    'waiting' => 1,
    'approved' => 2,
],

然后代码看起来像这样：

public function statusUpdate(Request $request)
{
    TravelRequest::where('id', $request->id)
        ->update(['status_id' => config('conf.status')[$request->status]]);

    return response()->json();        
}

Answer 3

public function statusUpdate(Request $request)
{
    $id = $request->id;                        //get the id
    $request['status_id'] = $request->status;  //get the status value on status_id
    DB::table('travel_request')
        ->where('id',$id )
        ->update(only(['status_id']));         //update only status_id field
    return response()->json();        
}

从表中获取值并更新laravel

3 个答案: