Question

我做了一个程序事务。如果错误，它应该报告位置错误。现在我想选择值TRUE和DELETE值TRUE

#!/usr/bin/python
import mysql.connector

conn = mysql.connector.connect(host="lll",user="ppp",passwd="ppp",db="ppp")
cursor = conn.cursor()

cursor.execute("SELECT(case when user1 = '1' THEN 'true' ELSE 'false' END) AS IsEmtpy from dt")
print(cursor.fetchall())

try:

    if true:
        cursor.execute("DELETE FROM dt WHERE user1='1'")
        print "DELETE SUCESS"
    else:
        print "DELETE ERROR"

        conn.commit()
except Exception as e:
        conn.rollback()
conn.close()

结果：

File "./splinsert.py", line 13
    if true:
     ^
IndentationError: expected an indented block

Answer 1

此错误与不一致的缩进有关。 Python依赖缩进来确定何时“代码块”启动和停止。 Take a look at this for more details

尝试这样的事情：

#!/usr/bin/python
import mysql.connector

conn = mysql.connector.connect(host="lll",user="ppp",passwd="ppp",db="ppp")
cursor = conn.cursor()

cursor.execute("SELECT(case when user1 = '1' THEN 'true' ELSE 'false' END) AS IsEmtpy from dt")
print(cursor.fetchall())

try:
  if True:
    cursor.execute("DELETE FROM dt WHERE user1='1'")
    print "DELETE SUCESS"
  else:
    print "DELETE ERROR"
    conn.commit()

except Exception as e:
  conn.rollback()

conn.close()

Python select数据返回boolean true-false和DELETE值true

1 个答案: