Question

我是一个python初学者，我想知道如何删除Python中列表中多次出现的项目。这是我的清单：

["0101013132","0101410142","0101430144"]

我想要做的第一件事是更换所有＆＃34; 01＆＃34;通过＆＃34; 1＆＃34;，第二件事就是取代＆＃34; 31＆＃34;，＆＃34; 32＆＃34; by＆＃34; 3＆＃34;分别替换＆＃34; 41＆＃34;，＆＃34; 42＆＃34;，＆＃34; 43＆＃34;，＆＃34; 44＆＃34; by＆＃34; 4＆＃34;分别

我不知道该怎么做。谢谢！

抱歉混淆。我想要的是将我的列表变成这个： [＆＃34; 11133＆＃34;＆＃34; 11414＆＃34;＆＃34; 11414＆＃34;]

Answer 1

my_list = ["0101013132","0101410142","0101430144"]
normalized_list = []
for item in my_list:
    normalized_list.append(item.replace('01', '1').replace('31', '3').replace('32', '3')) # and so one...)


print(normalized_list)

Answer 2

L = ["0101013132","0101410142","0101430144"]
answer = [s[::2].replace('0', '1') for s in L]

In [7]: answer
Out[7]: ['11133', '11414', '11414']

Answer 3

l =  ["0101013132","0101410142","0101430144"] 
[ ''.join( map( lambda x : str(x)[0]  ,map( int, map(''.join, zip( *( [iter(s)]*2) ) ) ) ) )  for s in l ]

如何删除Python中列表中多次出现的项目？

3 个答案: