我正在尝试在Web Api项目中实现2 Factor Authentication。但似乎2FA无法在Web Api中实现,其中AccountController继承了ApiController。是否可以在Web Api解决方案中实现2FA而不是MVC?
答案 0 :(得分:1)
问题非常广泛,但回答你的问题是可能的。
负责生成验证码的链接代码 -
public static class TimeSensitivePassCode
{
public static string GeneratePresharedKey()
{
byte[] key = new byte[10]; // 80 bits
using (var rngProvider = new RNGCryptoServiceProvider())
{
rngProvider.GetBytes(key);
}
return key.ToBase32String();
}
public static IList<string> GetListOfOTPs(string base32EncodedSecret)
{
DateTime epochStart = new DateTime(1970, 01, 01, 0, 0, 0, 0, DateTimeKind.Utc);
long counter = (long)Math.Floor((DateTime.UtcNow - epochStart).TotalSeconds / 30);
var otps = new List<string>();
otps.Add(GetHotp(base32EncodedSecret, counter - 1)); // previous OTP
otps.Add(GetHotp(base32EncodedSecret, counter)); // current OTP
otps.Add(GetHotp(base32EncodedSecret, counter + 1)); // next OTP
return otps;
}
private static string GetHotp(string base32EncodedSecret, long counter)
{
byte[] message = BitConverter.GetBytes(counter).Reverse().ToArray(); //Intel machine (little endian)
byte[] secret = base32EncodedSecret.ToByteArray();
HMACSHA1 hmac = new HMACSHA1(secret, true);
byte[] hash = hmac.ComputeHash(message);
int offset = hash[hash.Length - 1] & 0xf;
int truncatedHash = ((hash[offset] & 0x7f) << 24) |
((hash[offset + 1] & 0xff) << 16) |
((hash[offset + 2] & 0xff) << 8) |
(hash[offset + 3] & 0xff);
int hotp = truncatedHash % 1000000;
return hotp.ToString().PadLeft(6, '0');
}
}
public static class StringHelper
{
private static string alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ234567";
public static string ToBase32String(this byte[] secret)
{
var bits = secret.Select(b => Convert.ToString(b, 2).PadLeft(8, '0')).Aggregate((a, b) => a + b);
return Enumerable.Range(0, bits.Length / 5).Select(i => alphabet.Substring(Convert.ToInt32(bits.Substring(i * 5, 5), 2), 1)).Aggregate((a, b) => a + b);
}
public static byte[] ToByteArray(this string secret)
{
var bits = secret.ToUpper().ToCharArray().Select(c => Convert.ToString(alphabet.IndexOf(c), 2).PadLeft(5, '0')).Aggregate((a, b) => a + b);
return Enumerable.Range(0, bits.Length / 8).Select(i => Convert.ToByte(bits.Substring(i * 8, 8), 2)).ToArray();
}
}