Question

我正在尝试将列表的每个元素写在不同的文件中。

假设我们有一个清单：

dataset = ['abc', 'def', 'ghi']

我想遍历列表并根据列表的长度创建文本文件。因此，在这种情况下，应该有3个文本文件，每个文件将分别包含内容abc，def和ghi。

我目前的代码如下：

# This will read a text file, normalize it and remove stopwords from it using nltk.
import nltk, io, math
from nltk.corpus import stopwords

# Read raw text
targetFile = open('text.txt')
rawtext = targetFile.read()

# Removing stopwords
stops = set(stopwords.words('english'))
filtered_text = [i for i in rawtext.lower().split() if i not in stops]

# Count Number of words
total_words = len(filtered_text)

# Divide them equally into 10 different lists
chunk_size = math.floor(total_words/10)
n_lists_of_words = [filtered_text[i:i + chunk_size] for i in range(0, len(filtered_text), chunk_size)]
if(len(n_lists_of_words) > 10):
    del n_lists_of_words[-1]

# Lets make list of strings instead of list of lists
list_of_str = [' '.join(x) for x in n_lists_of_words]


# Create 10 different files from above 10 elements of n_list_of_words list
for index, word in enumerate(n_lists_of_words):
    with io.FileIO("output_text_" + str(index) + ".txt", "w") as file:
        file.write(bytes(word), 'UTF-8')

错误讯息：

Traceback (most recent call last):
  File "clean_my_text.py", line 35, in <module>
    file.write(bytes(word), 'UTF-8') 
TypeError: 'str' object cannot be interpreted as an integer

Answer 1

你的代码有点不对劲。这是最后一行更正。 file.write（bytes（dataset [count]，＆＃39; UTF-8＆＃39;））

Answer 2

谢谢大家。能做到这一点。以下是以下解决方案，请随时询问相关信息：

# This will read a text file, normalize it and remove stopwords from it using nltk.
import nltk, io, math
from nltk.corpus import stopwords
from string import punctuation

# Read raw text
targetFile = open('input_text.txt')
rawtext = targetFile.read()

# Remove punctuation
def strip_punctuation(s):
    return ''.join(c for c in s if c not in punctuation)
filtered_punc = strip_punctuation(rawtext)
print(filtered_punc)

# Removing stopwords
stops = set(stopwords.words('english'))
filtered_text = [i for i in filtered_punc.lower().split() if i not in stops]

# Count Number of words
total_words = len(filtered_text)

# Divide them equally into 10 different lists
chunk_size = math.floor(total_words/10)
n_lists_of_words = [filtered_text[i:i + chunk_size] for i in range(0, len(filtered_text), chunk_size)]
if(len(n_lists_of_words) > 10):
    del n_lists_of_words[-1]

# Lets make list of strings instead of list of lists
list_of_str = [' '.join(x) for x in n_lists_of_words]

# Print list values in seperate files
for index, word in enumerate(list_of_str):
    with open("Output" + str(index) + ".txt", "w") as text_file:
        print(word, file=text_file)

如何在单独的文本文件中编写列表的每个元素？

2 个答案: