Question

谢谢大家在前一部分的帮助。我现在已经完成了。然而，稍微改变标题和重新措辞问题我现在说这是我的代码。

s = raw_input("Enter your text: ")

longestWord = max(s.split(), key=len)

k = list(s)

count = len(k)

wordsOver = []

over = count - 140

def numLen(s, n):
    return sum(1 for x in s.split() if len(x) >= n)
    for x in s.split():
        if len(x) >= n:
            wordsOver.insert(0, x)

val = numLen(s, 7)

if count > 140:
    print ("Sorry, that is more than 140 characters.")
    print ("You had a total of " + str(count) + " characters.")
    print ("That's " + str(over) + " over the max allowed.")
    print ("You're longest word was, " + longestWord)
    print ("There are " + str(val) + " words over 7 characters.")
    print ("They were:")
    print (wordsOver)
    print ("You may want to consider changing them for shorter words.")
else:
    print ("That's short enough!")

所以现在我正在寻找的是为什么显示结束的单词不起作用，为什么以及如何解决它。顺便说一句，它有点帮助，这就是“有点破坏”这个词。

Answer 1

欢迎来到SO！

我认为这就是你想要做的。在您的numLen函数中，添加到列表时需要使用append()而不是insert()。这是因为当使用insert时，你没有递增索引，因此每次在索引0处插入时，都会覆盖已存在的任何值。附加功能可以找到列表末尾的位置，并将传递给它的内容放到最后。

s = raw_input("Enter your text: ")

longestWord = max(s.split(), key=len)

k = list(s)

count = len(k)

wordsOver = []

over = count - 140

def numLen(s, n):
    for x in s.split():
        if len(x) >= 7:
            wordsOver.append(x)
    return len(wordsOver)

val = numLen(s, 7)

if count > 140:
    print ("Sorry, that is more than 140 characters.")
    print ("You had a total of " + str(count) + " characters.")
    print ("That's " + str(over) + " over the max allowed.")
    print ("You're longest word was, \"" + longestWord + "\"")
    print ("There are " + str(val) + " words over 7 characters.")
    print ("They were:")
    print (wordsOver)
    print ("You may want to consider changing them for shorter words.")
else:
    print ("That's short enough!")

Answer 2

在for循环中，你正在查看每个字符，并检查该字符i是否是使用.isalpha()的字母表中的字符，当遇到空格时它将返回false，因为它是不是字母。

请参阅：https://docs.python.org/2/library/stdtypes.html#str.isalpha

Answer 3

isalpha（）不会为空格返回true。

此外，还有一系列更好的方法可以做到这一点。您应该查看集合中的Counter类。这是一本字典，可以为您提供所需的信息。

计算字符串Python中有多少单词超过某个限制

3 个答案: