Question

我需要通过调整高度条件来制作一个圆圈，这个程序使用了很多随机圆圈，但我不确定从哪里开始？我试图使用以下等式d =（sqrt）（（x1-x2）^ 2 +（y1-y2）^ 2）。现在该程序绘制了许多随机圆圈，因此调整公式我应该能够操纵它，以便某些圆圈在中心是红色的（如日本国旗）。

# using the SimpleGraphics library
from SimpleGraphics import *

# use the random library to generate random numbers
import random

diameter = 15


##
# returns a valid colour based on the input coordinates
#
# @param x is an x-coordinate 
# @param y is a y-coordinate 
# @return a colour based on the input x,y values for the given flag
##
def define_colour(x,y):
##

if y < (((2.5 - 0)**2) + ((-0.5 - 0)**2)**(1/2)):
c = 'red'
else:
c = 'white'

return c


return None


# repeat until window is closed
while not closed():

# generate random x and y values 
x = random.randint(0, getWidth())
y = random.randint(0, getHeight())

# set colour for current circle
setFill( define_colour(x,y) )

# draw the current circle
ellipse(x, y, diameter, diameter)

Answer 1

这是一些无休止地绘制圆圈的代码。靠近屏幕中心的圆圈将以红色绘制，所有其他圆圈将以白色绘制。最终，这将创建一个类似于日本国旗的图像，虽然内部红色“圆圈”的边缘不会平滑。

我没有测试过这段代码，因为我没有SimpleGraphics模块，而且通过Google或pip找到它并没有太大的成功。

from SimpleGraphics import *
import random

diameter = 15

width, height = getWidth(), getHeight()
cx, cy = width // 2, height // 2

# Adjust the multiplier (10) to control the size of the central red portion   
min_dist_squared = (10 * diameter) ** 2

def define_colour(x, y):
    #Calculate distance squared from screen centre
    r2 = (x - cx) ** 2 + (y - cy) ** 2
    if r2 <= min_dist_squared:
        return 'red'
    else:
        return 'white'

# repeat until window is closed
while not closed():
    # generate random x and y values 
    x = random.randrange(0, width)
    y = random.randrange(0, height)

    # set colour for current circle
    setFill(define_colour(x, y))

    # draw the current circle
    ellipse(x, y, diameter, diameter)

随机圈使用SimpleGraphics

1 个答案: