Question

这是一个MyLinkButton

<a id="btnUpdateActivityD"  style="margin: 10px 5px;" class="btn blue-soft pull-right">
    <i class="fa fa-check fa-lg"></i>&nbsp;Ok
</a>

那些是Ajax代码

  $("#btnUpdateActivityD").on('click', function () {
         var activity = new ActivityObject(parseInt(activityId), $("#txtActivityNameD").val(), $("#txtActivityCodeD").val(), startDate, endDate, true, parseInt($("#ddlActivityTypeD").val()), parseInt($("#ddlActivityCompD").val()), parseInt($("#ddlActivityTrainerD").val()), parseInt($("#ddlActivityPlaceD").val()), $("#txtActivityDescD").val(), parseInt(activityTotalPerson), 1);
            $.ajax({
                type: "POST",
                url: "ActivityDetail.aspx/UpdateActivity",
                data: "{act:" + JSON.stringify(activity) + "}",
                contentType: "application/json; charset=utf-8",
                dataType: "json",

                success: function (result) {
                    debugger;
                },
                error: function (result, textStatus, errorThrown) {
                    debugger;
                    //console.log(JSON.stringify(activityX));
                    //console.log("AJAX error: " + textStatus + ' : ' + errorThrown);
                },

            });

            window.parent.closeActivityDetailModal();
            window.parent.RefreshActivityList();
            window.parent.toastrNotification("success");


        });

大家好ajax post只能工作调试模式。如果项目正常运行，ajax post不起作用，捕获错误行并获得如result.responseText =“”的消息你能帮助我吗？我可以一次又一次地研究和审查我的文档，stacoverflow页面和代码块，但我没有解决。

Answer 1

试试这段代码

 $("#btnUpdateActivityD").on('click', function () {
         var activity = new ActivityObject(parseInt(activityId), $("#txtActivityNameD").val(), $("#txtActivityCodeD").val(), startDate, endDate, true, parseInt($("#ddlActivityTypeD").val()), parseInt($("#ddlActivityCompD").val()), parseInt($("#ddlActivityTrainerD").val()), parseInt($("#ddlActivityPlaceD").val()), $("#txtActivityDescD").val(), parseInt(activityTotalPerson), 1);
            $.ajax({
                type: "POST",
                url: "ActivityDetail.aspx/UpdateActivity",
                data: "{act:" + JSON.stringify(activity) + "}",
                contentType: "application/json; charset=utf-8",
                dataType: "json",

                success: function (result) {
                     window.parent.closeActivityDetailModal();
            window.parent.RefreshActivityList();
            window.parent.toastrNotification("success");

                },
                error: function (result, textStatus, errorThrown) {
                    debugger;
                    //console.log(JSON.stringify(activityX));
                    //console.log("AJAX error: " + textStatus + ' : ' + errorThrown);
                },

            });



        });

因为您使用的是ajax，所以回调和操作必须成功或错误方法

Ajax仅适用于调试模式

1 个答案: