Question

将字符串 a 传递给 myFunction（）时，我会传递引用。为什么退出时，引用指向旧String？它不使用字符串的实际引用吗？

import java.time.*;

public class Main {
    public static void main(String[] args) {
        String a = "aaa";

        myFunction(a);

        System.out.println(a);
    }

    private static void myFunction(String a) {
        a = a + "111";
        System.out.println(a);
    }
}

Answer 1

Look into variable scope. You are creating a local copy of the a variable and setting it in the myFunction() . The local copy only lives as long as the method does. When the Myfunction() completes its modified copy of the "a" is no longer reachable.

将String参数传递给函数并进行更改

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