Question

我在这里遇到一些问题jquery。所以我想使用数据库中的json对象创建一个自动完成文本字段，这里我提供了我的代码

jQuery：

$('#school_name').autocomplete({
    minLength: 3,
    autoFocus: true,
    source: function(request, response) {
            $.getJSON('https://host/path', { q: $('#school_name').val() }, 
    response);
}

返回Json

{
  "status": "success",
  "result": {
    "data": [
      {
        "school_id": xxx,
        "school_name": "xxx",
        "status": "Swasta",
        "address": "xxx",
        "city": "BANYUWANGI",
        "province": "JAWA TIMUR",
        "phone": "1234",
        "email": "xx@a.co",
        "picture": null,
        "is_published": "Y"
      },
      {
        "school_id": xxx,
        "school_name": "xxx",
        "status": "Swasta",
        "address": "  ",
        "city": "",
        "province": "",
        "phone": "-",
        "email": null,
        "picture": null,
        "is_published": "Y"
      }
    ]
  }
}

我不想要像我这样的返回值json对象，我只需要 school_name 的数组形式，请帮我解决我的问题

Answer 1

使用response回调来推送您想要的数据。

$('#school_name').autocomplete({
  minLength: 3,
  autoFocus: true,
  source: function(request, response) {

    $.get('https://host/path').always(function(res) {

      var json = JSON.parse(res), result_arr = [];
      $.each(json.result.data, function(k,v) {
          result_arr.push(v.school_name);
      });
      response(result_arr);

    });

  }
});

Answer 2

您可以使用Array.prototype.map转换数组。 map将对数组中的每个项运行一个函数，并使用返回的值创建一个新数组。

＆＃13;

const json = {
  "status": "success",
  "result": {
    "data": [
      {
        "school_id": '1234',
        "school_name": "First School Name",
        "status": "Swasta",
        "address": "xxx",
        "city": "BANYUWANGI",
        "province": "JAWA TIMUR",
        "phone": "1234",
        "email": "xx@a.co",
        "picture": null,
        "is_published": "Y"
      },
      {
        "school_id": '5678',
        "school_name": "Second School Name",
        "status": "Swasta",
        "address": "  ",
        "city": "",
        "province": "",
        "phone": "-",
        "email": null,
        "picture": null,
        "is_published": "Y"
      }
    ]
  }
}

console.log(
  json.result.data.map(school => school.school_name)
)

＆＃13;

jQuery autocomplate从json对象解析特定的数据数组

2 个答案: