Question

我的输出的一个重要部分是能够识别finalList的长度，但在我的代码中的某处，重复项被删除，我无法弄清楚

from itertools import chain, permutations
allPos = []
first_list = ['a','b','c']
match_list = [['a','b','c'], ['a','b','c']]

for i in range(1,30):
    for phrase in permutations(first_list, i):
        for ind, letter in enumerate(chain.from_iterable(phrase)):
             if ind >= len(match_list) or letter not in match_list[ind]:
                break
        else:
            allPos.append(phrase)

finalList = []

for i in allPos:
    if len(i) == len(allPos[-1]):
        finalList.append(i)

print(finalList)

输出

[('a', 'b'), ('a', 'c'), ('b', 'a'), ('b', 'c'), ('c', 'a'), ('c', 'b')]

我知道它正在删除重复项，或者我的代码可能完全丢失了一些东西，因为我从输出中遗漏了[('a','a'), ('b','b'), ('c','c')]

Answer 1

你可以试试这个。使用排列更改iterable。

from itertools import chain, permutations
...
...
for i in range(1,30):
    # change iterable
    for phrase in permutations([j for ele in match_list for j in ele], i):

...
for i in set(allPos):
    if len(i) == len(allPos[-1]):
        finalList.append(i)

print (sorted(finalList))
[('a', 'a'), ('a', 'b'), ('a', 'c'), ('b', 'a'), ('b', 'b'), ('b', 'c'), ('c', 'a'), ('c', 'b'), ('c', 'c')]

在我的代码中删除重复项的位置？

1 个答案: