根据SQL Server

Question

我的桌子上有一个到期日期列，我想按顺序提取记录。我使用了“按日期订购”的命令＆＃39;但它只按降序排列日期。

使用＆＃39; ORDER BY DATE＆＃39;

输出

2016-10-31
2016-10-06
2016-03-10

期望的输出：

2016-10-06
2016-10-31
2016-03-10

Answer 1

这是你想要的吗？

 order by abs(datediff(day, getdate(), [date]))

Answer 2

下面的SQL中有两件事。

1) First sort by date in descending order
2) With in each month sort the dates in ascending order of day.

（以下DATEPART功能将从DATE计算DAY。）

SELECT * 
  FROM DATA
ORDER BY DATEPART( MONTH, date ) DESC, DATEPART( DAY, date );

Answer 3

像戈登一样令人不安的辉煌，我认为有一种疏忽。

Declare @YourTable table (Date date)
Insert Into @YourTable values
('2016-10-14'),           -- Added 10/14 +4 Days
('2016-10-31'),
('2016-10-06'),
('2016-03-10')

Select *, NDays=datediff(day, getdate(), [date]) 
From @YourTable
Order By abs(datediff(day, getdate(), [date]))

返回

Date        NDays
2016-10-14  4          << Record Added (Should be below 10/6)
2016-10-06  -4
2016-10-31  21
2016-03-10  -214

我认为最安全（而且不那么优雅）会更像这样

Select *, NDays=datediff(day, getdate(), [date]) 
From @YourTable
Order By Year(Date) Desc,Month(Date) Desc,Day(Date)

返回

Date        NDays
2016-10-06  -4
2016-10-14  4
2016-10-31  21
2016-03-10  -214