我正在尝试在表格单元格上添加边框,但我无法弄清楚如何使用rowspan。
我想要一个有4个单元格的表 左边有1个大单元,右边有3个小单元。
这是我使用的代码
的jsfiddle [点]净/ 1fv4dz5g / 3 /
答案 0 :(得分:2)
这可以使用CSS完成。检查此css示例
td {
border: 1px solid black;
}

<table class="tnews-side" border="0">
<tr>
<td rowspan="3">
<table border="1" cellpadding="4" cellspacing ="0">Row 1 Cell 1</table>
</td>
<td>Row 1 Cell 2</td>
</tr>
<tr>
<td>Row 2 Cell 2</td>
</tr>
<tr>
<td>Row 2 Cell 2</td>
</tr>
</table>
&#13;
答案 1 :(得分:0)
使用CSS有两种方法:
设置每个/所有import math
import time
primfac=[]
def primcheck(n):
for x in xrange(2, int(n**0.5)+1):
if n % x == 0:
return False
return True
def primes(n):
sieve = [True] * n
for i in xrange(3,int(n**0.5)+1,2):
if sieve[i]:
sieve[i*i::2*i]=[False]*((n-i*i-1)/(2*i)+1)
return [2] + [i for i in xrange(3,n,2) if sieve[i]]
def factfind(lsp,n): #finds factors of n among primes
for i in lsp:
if n%i==0:
primfac.append(i)
else:
i+=1
def simplify(lsp, n):
x = 1
for i in lsp:
x=i*x
if x != n:
print "needs exponent, computing"
for i in lsp:
y=n/i
if primcheck(y) == True:
lsp.append(y)
else:
lsp.append(factfind(primes,y))
def primfacfind(n1,n2):
global primfac
while n1 <= n2:
time_start = time.clock()
if primcheck(n1) == True:
print "prime"
time_elapsed = time.clock() - time_start
print "time:", time_elapsed
n1+=1
else:
n = n1
print "starting #", n
factfind(primes(n),n)
print primfac
del primfac
primfac = []
simplify(primfac, n)
time_elapsed = time.clock() - time_start
print "time:", time_elapsed
n1+=1
primfacfind(6,15)
一个类并使用css border:
td
或者您可以使用嵌套选择或<style>
.bigCell{border:1px solid black;}
.smallCell{border-left:1px solid black;}
</style>
...
<td class="biCell">
...
<td class="smallCell">
选择器
:nth-child()
你可以查看:
https://css-tricks.com/almanac/selectors/n/nth-child/