Question

我有这个字符串：

http://sh.st/st/8052f1bbc624add41cd2a6236f76cfc8/https://www.rapidvideo.com/embed/o1cTaZbux

我想将网址与此分开提取。

我的代码：

$pattern = '@((https?://)?([-\\w]+\\.[-\\w\\.]+)+\\w(:\\d+)?(/([-\\w/_\\.]*(\\?\\S+)?)?)*)@';

$str= "http://sh.st/st/8052f1bbc624add41cd2a6236f76cfc8/https://www.rapidvideo.com/embed/o1cTaZbux";

if($num_found = preg_match_all($pattern, $str, $out))
{
  echo "FOUND ".$num_found." LINKS:\n";
  print_r($out[0]);
}

但输出错误：

Array
(
    [0] => http://sh.st/st/8052f1bbc624add41cd2a6236f76cfc8/https
    [1] => www.rapidvideo.com/embed/o1cTaZbux
)

我想输出：

Array
(
    [0] => http://sh.st/st/8052f1bbc624add41cd2a6236f76cfc8
    [1] => https://www.rapidvideo.com/embed/o1cTaZbux
)

请帮忙

Answer 1

也许没有语句等乐趣，并通过函数preg_split来完成？

EG。 $urls = preg_split('/ (http|https) /', $str, PREG_SPLIT_DELIM_CAPTURE);

修改

要执行此操作，您必须添加新标记+相互添加结果。

$urls = preg_split('/(http|https)/', $str, -1, PREG_SPLIT_DELIM_CAPTURE | PREG_SPLIT_NO_EMPTY); foreach ($urls as $k => $v) { if ($k % 2 != 0) { continue; } $list[] = $urls[$k].$urls[$k+1]; }

Answer 2

$str= "http://sh.st/st/8052f1bbc624add41cd2a6236f76cfc8/https://www.rapidvideo.com/embed/o1cTaZbux";


$foo = preg_split('#(http://)|(https://)#', $str,0,PREG_SPLIT_NO_EMPTY | PREG_SPLIT_DELIM_CAPTURE);



for ($i = 0; $i < sizeof($foo); $i += 2) {
    $delim = isset($foo[$i + 1]) ? $foo[$i + 1] : '';
    $tmp[] = $foo[$i] . $delim;
}
print_r($tmp);

阵列（
      [0] =＆gt; http://sh.st/st/8052f1bbc624add41cd2a6236f76cfc8/
      [1] =＆gt; https://www.rapidvideo.com/embed/o1cTaZbux
）

从字符串中提取网址

2 个答案: