我正在使用“编码员的学徒：使用Python 3学习Python”（http://www.spronck.net/pythonbook/pythonbook.pdf）。
我正在做这个练习：“一本书的封面价格是24.95美元，但书店可以获得40％的折扣。 第一份副本的运费为3美元，每份额外的副本为75美分。计算60份的批发总成本。“
这是我的代码：
jconsole无论出于何种原因，这行代码中的单词book_price = 24.95
book_discount = book_price / 10 * 4
bookstore_book_price = book_price - book_discount
shipping_first = 3
shipping_rest = 0.75
sixty_shipped = bookstore_book_price + shipping_first + (shipping_rest * 59)
print("A book is being sold regularly for " +str(book_price) + ".")
print("At bookstores, it's being sold with a 40% discount, amounting to " + str(book_discount) + ".")
print("This means it's being sold at bookstores for " + str(bookstore_book_price) + ".")
print("The first copy ships for " + "str(shipping_first) + ", but the rest ships for " + str(shipping_rest) ".")
print("Given 60 copies were shipped, it would cost " + str(sixty_shipped + ".")
：
the产生语法错误。鉴于我删除了每个单词，直到我到达(print("The first copy ships for " + "str(shipping_first) + ", but the rest ships for " + str(shipping_rest) "."))`
，我仍然会收到语法错误。如果只剩下for和for，则会出现错误：
扫描字符串文字时的EOL
产生了。我不知道该怎么做。
答案 0 :(得分：1)
因为你有额外的"。而不是
(print("The first copy ships for " + "str(shipping_first) + ", but the rest ships for " + str(shipping_rest) "."))
DO
(print("The first copy ships for " + str(shipping_first) + ", but the rest ships for " + str(shipping_rest) + "."))
您还可以从print() docs
str()
所有非关键字参数都转换为字符串，如str（），并写入流
<强> UPD
您还在错误行末尾跳过了+。
正如@tobias_k提到的那样，您忘记了)方法str
print("Given 60 copies were shipped, it would cost " + str(sixty_shipped + ".")
因此，您的代码可以在没有str()方法的情况下工作：
print("The first copy ships for ", shipping_first, ", but the rest ships for ", shipping_rest, ".")
或者更好format()
print("The first copy ships for {}, but the rest ships for {}.".format(shipping_first, shipping_rest))
它现在更具可读性。