Question

我想显示一个带有两个按钮的确认框是和否，当用户按下是否会显示索引页面时，当用户按下此按钮时，重定向到另一个页面。这确认msgbox只显示一次，当第一次网站打开而不是每次重新加载页面时。感谢

Answer 1

你可以试试这段代码

 <script>
 var confirm = confirm("sample message?");
 if(confirm) {
     // index page
     window.location.url = ""; // your url index page
  } else {
     // other page
     window.location.url = ""; // your url other page
  }
 </script>

Answer 2

你必须在javascript中做所有的事情。您可以使用的Javascript函数。您还需要在浏览器中设置cookie并检查cookie是否已设置。

function myFunction() {
    var x;
    if (confirm("Press a button!") == true) {
        x = "You pressed OK!";
    } else {
        x = "You pressed Cancel!";
    }
    document.getElementById("demo").innerHTML = x;
}

希望这有帮助。

Answer 3

function myFunction() {
    var txt;
    var r = confirm("Press a button!");
    if (r == true) {
        txt = "You pressed OK!";
    } else {
        txt = "You pressed Cancel!";
    }
    document.getElementById("demo").innerHTML = txt;
}

<button onclick="myFunction()">Try it</button>

<p id="demo"></p>

Answer 4

void loop() {
  for (int fade=0; fade <=100; fade=fade+5) //<- NO SEMICOLON
  {  //<- OPENING BRACE
    analogWrite (red, fade);
    delay(30);
    digitalWrite(red, 0); analogWrite (green, fade);
    delay(30);
    digitalWrite(green, 0); analogWrite (blue, fade);
    delay(30);
    digitalWrite(blue, 0);
  }  // <- CLOSING BRACE

}

如何在php网站上显示确认框

4 个答案: