尝试向mysql插入时间时出现此错误。
“时间值不正确......”
我的控制器:
//Create the video player and set the video path
videoPlayerView = (VideoView) rootView.findViewById(R.id.video_area);
if (videoPlayerView == null) {
Log.d("VideoPlayer Activity","onCreateView: videoPlayerView is null");
return null;
}
//Set the video URI to the the URL of the video on the server
videoPlayerView.setVideoURI(yourVideoURL);
我的观点和javascript:
$data = array(
'branch_open_time' => date("H:i:s",strtotime($this->input->post('time_range_from'))),
'branch_close_time' => date("H:i:s",strtotime($this->input->post('time_range_to')))
);
$this->db->insert('branch_user',$data);
$this->db->insert_id();
jQuery的:
<div id="datetimepicker" class="input-append" style="resize: none;" data-autoclose="true">
<label for="open">Waktu Buka</label><br />
<div class="input-group">
<input data-format="HH:mm PP" type="text" class="form-control" name="time_range_from" id="time_range_from">
<span class="add-on input-group-addon" style="height: 30px">
<i class="glyphicon glyphicon-time"></i>
</span>
</div>
</div>
<div id="datetimepicker2" class="input-append" style="resize: none;" data-autoclose="true">
<label for="open">Waktu Tutup</label><br />
<div class="input-group">
<input data-format="HH:mm PP" type="text" class="form-control" name="time_range_to" id="time_range_to">
<span class="add-on input-group-addon" style="height: 30px">
<i class="glyphicon glyphicon-time"></i>
</span>
</div>
</div>
添加功能:
$(function() {
$('#datetimepicker').datetimepicker
({
pick12HourFormat: true,
language: 'en',
pickDate: false
});
$('#datetimepicker2').datetimepicker
({
pick12HourFormat: true,
language: 'en',
pickDate: false
});
});
时间戳正确显示12小时格式,我在插入数据库之前将其从H:i:s转换为strtotime,但它无效。我做错了什么?
datetimepicker输入:
答案 0 :(得分:1)
该行
echo date("H:i:s",strtotime('05 : 54 : 51 PM'));
会产生00:00:00
然而
echo date("H:i:s",strtotime('05:54:51 PM'));
或
echo date("H:i:s",strtotime('05:54:51PM'));
会产生17:54:51
因此,在将数据发送到INSERT命令之前,您需要在javascript或PHP代码中修剪这些空格
例如
$t1 = date('H:i:s', str_replace(' ', '', $this->input->post('time_range_from')));
$t2 = date('H:i:s', str_replace(' ', '', $this->input->post('time_range_to')));
$data = array(
'branch_open_time' => $t1,
'branch_close_time' => $t2
);
$this->db->insert('branch_user',$data);
$this->db->insert_id();
答案 1 :(得分:-1)
一切都是平等的:
将您的代码更新为:
我在变量前添加了var以将其建立为变量
function add_location(){
var branch_open_time = $("#time_range_from").val();
var barnch_close_time = $("#time_range_to").val();
$.ajax({
url : 'add_location',
type: "POST",
dataType: "text",
data:{
time_range_from: branch_open_time,
time_range_to: barnch_close_time
},
success: function(data)
{
location.reload();
},
error: function (jqXHR, textStatus, errorThrown)
{
alert('Error data');
}
});
}
日期中的空格在插入
之前使其无效使用此选项从日期中删除空格以使其成为有效空间:
str_replace(' ','',$date);