Question

我是编程新手，并且不断出现。

这是我的connect.php

<?php

    $username = "root";
    $password = "";
    $db = "app";

    // Create connection

    $conn = mysqli_connect("localhost", $username, $password, $db);

    if (!@$conn) {
    die ("Unable to Connect!");
    }
    else {
    echo "Connected!";
    }

?>

并且错误一直显示在此代码中（index.php）错误说

致命错误：未捕获错误：在C：\ xampp \ htdocs \ nath \ index.php中调用字符串上的成员函数query（）：5堆栈跟踪：＃0 {main}在C：\ xampp \ htdocs中抛出第5行的\ nath \ index.php

<?php
error_reporting(E_ALL);
require 'db/connect.php'; 

if ($update = $db->query("UPDATE people SET created = NOW()")) {

 }


 ?>

Answer 1

试试这个：

if ($update = $conn->query("UPDATE people SET created = NOW()")) {
    echo "Data updated.";
}

$db = 'app';您可以使用$db->query();来解决错误原因。因此，更正为$conn->query('your query');

Answer 2

<?php
error_reporting(E_ALL);
require 'db/connect.php'; 

if ($update = $conn->query("UPDATE people SET created = NOW()")) {

 }


 ?>

$update = $conn->query因为您的关联是$conn而不是$db

Answer 3

error_reporting(E_ALL);
require 'db/connect.php'; 

    // Create connection
    $conn = new mysqli($servername, $username, $password, $dbname);
    // Check connection
    if ($conn->connect_error) {
        die("Connection failed: " . $conn->connect_error);
    }

    $sql = "UPDATE people SET created = NOW()";

    if ($conn->query($sql) === TRUE) {
        echo "Record updated successfully";
    } else {
        echo "Error updating record: " . $conn->error;
    }

    $conn->close();

Answer 4

我建议您使用PDO而不是mysqli。所以你可以声明一个这样的类：

class DataBase
{
    var $database_name = "your_database_name_here";
    var $database = null;

    public function __construct()
    {
        $user = "root";
        $password = "";
        try {
            $this->database = new PDO('mysql:host=localhost;dbname=' . $this->database_name, $user, $password);
        } catch (PDOException $e) {
            exit("Fatal error: " . $e->getMessage());
        }
    }

    public function get_database()
    {
        return $this->database;
    }
}

然后你可以使用：

$database_object = new DataBase();
$database = $database_object->get_database();

最后，要进行查询，您可以执行以下操作：

$database->query("select * from foo");

mysql中query（）错误导致的致命错误

4 个答案: