Question

我只是尝试通过Swift3 httprequest发送JSON字符串。

尝试使用词典和转义字符串......

func getToken(successHandler: @escaping (Any) -> Void, errorHandler: @escaping (Any) -> Void) {

    var request = URLRequest(url: URL(string: "http://my-api.domain.com/getToken")!)

    request.httpMethod = "POST"

    request.setValue("application/json", forHTTPHeaderField: "Content-Type")

    do
    {
        // try with Dictionary
        let bodyJson: [String: String] = [
            "username": "theusername"
        ]
        let bodyJsonData = try JSONSerialization.data(withJSONObject: bodyJson, options: [])

        // try with escaped String
        let jsonString = "{" +
            "\"username\": \"theusername\"," +
        "}"
        let jsonStringData = jsonString.data(using: String.Encoding.utf8)


        //request.httpBody = bodyJsonData
        request.httpBody = jsonStringData


        let task = URLSession.shared.dataTask(with: request) { data, response, error in
            guard error == nil else {
                print(error)
                errorHandler(error)
                return
            }
            guard let data = data else {
                print("Data is empty")
                errorHandler("Data is empty")
                return
            }

            var json: Any? = nil
            do
            {
                json = try JSONSerialization.jsonObject(with: data, options: [])

                DispatchQueue.main.asyncAfter(deadline: .now()) {
                    successHandler(json)
                }
            }
            catch let error as NSError {
                errorHandler(error)
            }
        }

        task.resume()
    }
    catch
    {
        errorHandler(error)
    }
}

我一直在：

处理错误：错误域= NSCocoaErrorDomain代码= 3840＆＃34; JSON文本确实如此不要从数组或对象和选项开始，以允许未设置片段。＆＃34; UserInfo = {NSDebugDescription = JSON文本不是以数组或允许片段未设置的对象和选项。}

我无法找到如何尝试允许片段，所有示例/教程都适用于Swift2.x：/

不确定该怎么做！

POST w / JSON Body - Swift3 - 片段？

1 个答案: