Question

我是新手来堆叠溢出，所以请忍受格式化这是一个真正的问题

我正在创建一个程序来复制，删除和移动文件，但仍无法解决错误的回声错误，我该怎么办？我已经阅读了另一个相关的问题，其中包括一个;但这也没有解决问题

    #!/bin/bash
    echo "Menu "
    echo "1. Copy a File "
    echo "2. Remove a file "
    echo "3. Move a file"
    echo "4. Quit"
    echo "Enter ur Choice \c"
    read Choice
    case " $Choice " in 
    1. echo "Enter File name to copy \c" 
           read f1
       echo " Enter File name \c "  
      read f2         
      if [ -f $f1 ]
      then
      cp $f1 $f2
          else
                 echo "$f1 does not exist"
          fi
          ;;
      2. echo "Enter the File to be removed "
         read r1
         if [ -f $r1 ]
         then      
         rm -i $r1
         else 
              echo "$r1 file does not exist "
         fi
         ;;
      3.
         echo "Enter File name to move \c"
         read f1
         echo "Enter destination \c "
         read f2
         if [ -f $f1 ]
         then 
             if [ -d $f2 ]
             then
                  mv $f1 $f2
             fi
         else
         echo "$f1 does not exist"
         fi
         ;;
     4. 
         echo "Exit......."
         exit;;
         esac

错误

    ./script13.sh: line 10: syntax error near unexpected token `echo'
    ./script13.sh: line 10: `       1. echo "Enter File name to copy \c " '
    root@Kalilinux1:~/bin#

Answer 1

你缺少括号，所以：

#!/bin/bash
echo "Menu "
echo "1. Copy a File "
echo "2. Remove a file "
echo "3. Move a file"
echo "4. Quit"
read -p "Enter ur Choice >>> "
case " $Choice " in  
    1) echo "Enter File name to copy \c" 
        read f1 
        echo " Enter File name \c "  
        read f2
        if [ -f $f1 ]
        then
            cp $f1 $f2
        else
            echo "$f1 does not exist"
        fi
        ;;
    2) echo "Enter the File to be removed "
        read r1
        if [ -f $r1 ]
        then 
            rm -i $r1
        else 
            echo "$r1 file does not exist "
        fi
        ;;
    3)
        echo "Enter File name to move \c"
        read f1
        echo "Enter destination \c "
        read f2
        if [ -f $f1 ]
        then 
            if [ -d $f2 ]
            then
                mv $f1 $f2
            fi
        else
            echo "$f1 does not exist"
        fi
        ;;
    4) 
        echo "Exit......."
        exit;;
esac

Answer 2

而不是第10行中的1.，您应该使用1)。执行案例陈述的正确方法是：

case "$Choice" in 
  1) ...
     ;;
  2) ...
     ;;

另外，删除" $Choice "中的空格。

意外令牌`echo'附近的语法错误

2 个答案: