Question

在打开我的网站时，我根本无法理解为什么我没有看到表格？我想要一个由机器人用户名，密码和子框出现的表格，虽然我在这里看不到解决方案......

非常感谢解决方案和解释。

  <?php
   error_reporting(E_ALL ^ E_NOTICE);
   session_start();
   ?>
<!DOCTYPE html>
<!-- 
-->
   <html>
   <head>
   <meta charset="UTF-8">
   <title>World Talk Login</title>
   </head>
   <body>
   <?php
    $form = "<form action='./login.php' method='post'>
   <table>
   <tr>
   <td>Username:</td>
   <td><input type='text' name='user'/></td>
   </tr>
   <tr>
  <td>Password:</td>
  <td><input type='password' name='password'/></td>
  </tr>
  <tr>
  <td></td>
  <td><input type='submit' name='loginbtn' value='Login'/></td>

  </tr>
  </table>
  </form>";            

  if ($_POST['loginbtn']){
  $user = $_POST ['user'];
  $password = $_POST['password'];

  if ($user) {
  if ($password){
  echo "$user - $password <hr /> $form";
  }
  else
  echo "You must enter your password. $form";
 }
 else
 echo "You must enter your username. $form";
 }
 ?>

</body>
</html>

提前感谢！

Answer 1

您没有从PHP打印表单或错误地将表单包装在PHP中。它包含在变量<?php中的$form标记周围，但没有打印到屏幕。

如果错误正常工作，它应该如下所示;-)

 <?php
   ini_set('display_errors', 1);
   ini_set('display_startup_errors', 1);
   error_reporting(E_ALL);
   session_start();
   ?>
<!DOCTYPE html>
<!--

-->
   <html>
   <head>
   <meta charset="UTF-8">
   <title>World Talk Login</title>
   </head>
   <body>

   <form action='./login.php' method='post'>
   <table>
   <tr>
   <td>Username:</td>
   <td><input type='text' name='user'/></td>
   </tr>
   <tr>
  <td>Password:</td>
  <td><input type='password' name='password'/></td>
  </tr>
  <tr>
  <td></td>
  <td><input type='submit' name='loginbtn' value='Login'/></td>

  </tr>
  </table>
  </form>

<?php

  if ($_POST['loginbtn']){
  $user = $_POST ['user'];
  $password = $_POST['password'];

  if ($user) {
  if ($password){
  echo "$user - $password <hr /> $form";
  }
  else
  echo "You must enter your password. $form";
 }
 else
 echo "You must enter your username. $form";
 }
 ?>

</body>
</html>

Answer 2

你也没有回应你的变量

Answer 3

尝试将底部的php更改为以下内容。

if ($_POST['loginbtn']){
    $user = $_POST ['user'];
    $password = $_POST['password'];

    if($user != "" && $password != "") {
        echo "$user - $password <hr /> $form";
    }

    if($user == "") {
        $error .= "You must enter your username.</br>";
    }

    if($password == "") {
        $error .= "You must enter your password.";
    }

    if($error != "") {
        echo $error.$form;
    }
} else {
    echo $form;
}

Answer 4

 <html>
   <head>
   <meta charset="UTF-8">
   <title>World Talk Login</title>
   </head>
   <body>
   <?php
    $form = "<form action='./login.php' method='post'>
   <table>
   <tr>
   <td>Username:</td>
   <td><input type='text' name='user'/></td>
   </tr>
   <tr>
  <td>Password:</td>
  <td><input type='password' name='password'/></td>
  </tr>
  <tr>
  <td></td>
  <td><input type='submit' name='loginbtn' value='Login'/></td>

  </tr>
  </table>
  </form>";

  echo $form;


  if (!isset($_POST['loginbtn'])){
  $user = (!isset($_POST['user']));
  $password = (!isset($_POST['password']));
}
  else{

  }

  ?>

</body>
</html>

php html为什么我的表单不在网页上显示？

4 个答案: