Question

如何将发布或插入照片或文本的方式分开到我的数据库，即mysql数据库。

在这行代码中，我可以将图片和文本一起发布，但如果我只想要一张图片，则会在代码中显示错误。

<?php
include('includes/database.php');
include('session.php');

if (!isset($_FILES['image']['tmp_name'])) {
    echo "";
}else{
    $file=$_FILES['image']['tmp_name'];
    $image = $_FILES["image"] ["name"];
    $image_name= addslashes($_FILES['image']['name']);
    $size = $_FILES["image"] ["size"];
    $error = $_FILES["image"] ["error"];

    if ($error > 0){
        die("Error uploading file! Code $error.");
    }else{
        if($size > 10000000){ //conditions for the file
            die("Format is not allowed or file size is too big!");
        }else{

            move_uploaded_file($_FILES["image"]["tmp_name"],"upload/" . $_FILES["image"]["name"]);          
            $location="upload/" . $_FILES["image"]["name"];
            $user=$_SESSION['id'];
            $content=$_POST['content'];
            $time=time();

            $update=mysql_query(" INSERT INTO post (user_id,post_image,content,created)
            VALUES ('$id','$location','$content','$time') ") or die (mySQL_error());

        }
    header('location:home.php');
    }
}
?>

这是与上述代码相对应的表格。

<div id="right-nav">
    <h1>Update Status</h1>
    <form method="post" action="post.php" enctype="multipart/form-data">
        <textarea placeholder="Whats on your mind?" name="content" class="post-text" required></textarea>
        <input type="file" name="image">
        <button class="btn-share" name="Submit" value="Log out">Share</button>
    </form>
</div>

感谢您将来的答案。

Answer 1

保存图像或文本或两者：

<?php
include('includes/database.php');
include('session.php');

$user=$_SESSION['id'];
$time=time();

// Content
if( isset($_POST['content']) && !empty($_POST['content']) ){
    $content=$_POST['content'];
}else{
    $content="";
}

// Image
if ( isset($_FILES['image']['tmp_name']) && !empty($_FILES['image']['tmp_name']) ) {
    $file=$_FILES['image']['tmp_name'];
    $image = $_FILES["image"] ["name"];
    $image_name= addslashes($_FILES['image']['name']);
    $size = $_FILES["image"] ["size"];
    $error = $_FILES["image"] ["error"];

    if ($error > 0){
        die("Error uploading file! Code $error.");
    }
    if($size > 10000000){ //conditions for the file
        die("Format is not allowed or file size is too big!");
    }

    move_uploaded_file($_FILES["image"]["tmp_name"],"upload/" . $_FILES["image"]["name"]);          
    $location="upload/" . $_FILES["image"]["name"];
}else{
    $location="";
}

// Save to database if there is content OR an image
// Will save both if both are present

if( !empty($content) || !empty($location) ){
    $update=mysql_query(" INSERT INTO post (user_id,post_image,content,created)
    VALUES ('$id','$location','$content','$time') ") or die (mySQL_error());

    // Redirect to home
    header('location:home.php');
}
?>

在所有情况下，都会设置SQL查询所需的变量所以应该没有错误。

如果没有文字且没有图像，则脚本什么都不做。

如何使用php分别插入照片和文字？

1 个答案: