我的一项任务有以下问题:
程序的一个功能(功能#2)是读入实例文件的内容。读入 文件" instance10 001.txt "你将执行命令:
NameOfProgram -i instance10 001.txt
这里" -i"是命令行选项,指示后续参数是 输入文件名。
这是我到目前为止所做的,主要是骨架:
/* Assignment 1 */
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <time.h>
int main(int argc, char *argv[])
{
FILE *fp;
int max_x, max_y, num_pt, rand_inst;
int *x_coordinate, *y_coordinate;
int inputfile = 0, outputfile = 0;
int i;
if (argc == 1)
{
/* to generate random instances, accepting parameters from stdin */
printf("Generating random instances...");
printf("Enter the circuit board size MAX_X MAX_Y: ");
scanf("%d %d", &max_x, &max_y);
printf("Enter the number of points NUM_PT: ");
scanf("%d", &num_pt);
printf("Enter the number of random instances to be generated: ");
scanf("%d", &rand_inst);
return 1;
}
for (i = 1; i < argc; i++)
{
if (strcmp (argv[i], "-i") == 0)
inputfile = i+1;
else if (strcmp (argv[i], "-o") == 0)
outputfile = i+1;
}
if (inputfile == 0)
{
/* invalid comman line options */
printf("\nIncorrect command-line\n");
printf("myprogram [-i inputfile [-o outputfile]]");
return -1;
}
**/* THIS IS WHERE I NEED HELP */**
if (inputfile == 1)
{
fp = fopen(/*Name of the input file (instance10_001.txt) */, "r")
}
if ((fp = fopen(argv[inputfile], "r")) == NULL)
{
/* open file error */
return -2;
}
while (fscanf(fp, "%d", &max_x) != 1)
{
if (ferror(fp))
{
/* read error */
fclose(fp);
return -3;
}
if (feof(fp))
{
/* no integer to read */
fclose(fp);
return -4;
}
fscanf(, "%*[^\n]"); /*skip the rest of line */
}
if (fscanf(fp, "%d", &max_y) != 1)
{
/* max_y not following max_x */
fclose(fp);
return -5;
}
while (fscanf(fp, "%d", &num_pt) != 1)
{
if(ferror(fp))
{
/* read error */
fclose(fp);
return -6;
}
if (feof(fp))
{
/* no integer to read */
fclose(fp);
return -7;
}
fscanf(fp, "%*[^\n]"); /* skip the rest of line */
}
x_coordinate = (int *)malloc(num_pt * sizeof(int));
y_coordinate = (int *)malloc(num_pt * sizeof(int));
for (i = 0; i < num_pt; i++)
{
while (fscanf(fp, "%d", &x_coordinate[i]) != 1)
{
if (ferror(fp))
{
/* read error */
fclose(fp);
return -8;
}
if (feof(fp))
{
/* no integer to read */
fclose(fp);
return -9;
}
fscanf(fp, "%*[^\n]"); /* skip the rest of line */
}
if (fscanf(fp, "%d", &y_coordinate[i]) != 1)
{
/* y_coordinate not following x_coordinate */
fclose(fp);
return -10;
}
}
fclose(fp);
if (outputfile > 0)
{
if ((fp = fopen(argv[outputfile], "w")) == NULL)
{
/* open file error */
return -2;
}
fprintf(fp, "##################################################\n");
fprintf(fp, "#%s\n", argv[inputfile]);
fprintf(fp, "#area [0, MAX_X] x [0, MAX_Y]\n");
fprintf(fp, "%d\t%d\n", max_x, max_y);
fprintf(fp, "#number of points NUM_PT\n");
fprintf(fp, "%d\n", num_pt);
fprintf(fp, "#coordinates\n");
for (i = 0; i < num_pt; i++)
{
fprintf(fp, "%d\t%d\n", x_coordinate[i], y_coordinate[i]);
}
fprintf(fp, "#end of instance\n");
fclose(fp);
}
else
{
printf("##################################################\n");
printf("#%s\n", argv[inputfile]);
printf("#area [0, MAX_X] x [0, MAX_Y]\n");
printf("%d\t%d\n", max_x, max_y);
printf("#number of points NUM_PT\n");
printf("%d\n", num_pt);
printf("#coordinates\n");
for (i = 0; i < num_pt; i++)
{
printf("%d\t%d\n", x_coordinate[i], y_coordinate[i]);
}
printf("#end of instance\n");
}
free(x_coordinate);
free(y_coordinate);
return 0;
}
我想知道如何从bash终端读取输入文件的名称。我应该使用scanf吗?
如何获取用户输入的内容作为输入文件?例如,如果用户使用./myprogram -i instance10_001.txt
从bash运行我的程序,如何在程序中打开输入的文件?
PS我正在使用我的Ubuntu终端通过ssh访问我的实验室计算机。
语言:c99;编译器:gcc
答案 0 :(得分:1)
这看起来像你的if语句中的一个简单错误。你只是说,如果inputfile是1(这意味着-o必须是argv [0]),它将打开inputfile。
vm.maquina_id
另外,这里还有另一个问题,你将fp分配给一个函数,然后重新打开已在fp中打开的文件:
visitamaquina
此外,在这段代码中:
reporteproducto
Fscanf返回成功填充的参数数量,在这种情况下,将始终为1 请注意,代码的其余部分可能存在类似的问题。