Question

我有一个包含以下字段的表

Supervisorid
EMPID

这就像推荐计划一样。一个人可以推荐他下面的3个人，即 3是指三个人即4 5 8同样4指的是9 10和11同样8指的是12,13它是这样的..

我想要一个查询来获得一个人说3下的总行数。

Answer 1

您可以使用递归CTE。

像这样的东西

DECLARE @Table TABLE(
        Supervisorid INT,
        Empid INT
)

INSERT INTO @Table SELECT 3, 4
INSERT INTO @Table SELECT 3, 5
INSERT INTO @Table SELECT 3, 8

INSERT INTO @Table SELECT 4, 9
INSERT INTO @Table SELECT 4, 10
INSERT INTO @Table SELECT 4, 11

INSERT INTO @Table SELECT 8, 12
INSERT INTO @Table SELECT 8, 13

DECLARE @ID INT
SELECT  @ID = 3

;WITH Vals AS (
        SELECT  *
        FROM    @Table
        WHERE   SuperVisorID = @ID
        UNION ALL
        SELECT  v.SuperVisorID,
                t.Empid
        FROM    Vals v INNER JOIN
                @Table t    ON  v.Empid = t.Supervisorid
)
SELECT  SuperVisorID,
        COUNT(Empid) Total
FROM    Vals
GROUP BY    SuperVisorID

Sql Server 2005查询问题

1 个答案: