我有两个查询，几乎相似，但从不如此，它们必须被视为独立的，因为它们具有不同的含义和价值，我想将它们组合成一个视图，我绑在做UNION，但是结果是它们都被合并到一个表中，这不是我想要的，我希望它们在一个视图下显示为完全独立的表，这是我做的：
CREATE VIEW TEAM_SUMMARY AS
SELECT DISTINCT COUNTRY.country_name AS CountryName_T1,count(Team1)AS NoOfGames,
SUM(Team1_score) AS TotalGoalsFor,SUM(Team2_score) AS TotalGoalsAgainst
FROM COUNTRY,MATCH_RESULTS WHERE
country_name = Team1
group by country_name
UNION
SELECT DISTINCT COUNTRY.country_name AS CountryNameT_2,count(Team2)AS NoOfGames,
SUM(Team2_score) AS TotalGoalsFor,SUM(Team1_score) AS TotalGoalsAgainst
FROM COUNTRY,MATCH_RESULTS WHERE
country_name = Team2
group by country_name;
更新： 所以，我当前查询的输出是这样的：
mysql> SELECT * FROM TEAM_SUMMARY;
+----------------------+-----------+---------------+-------------------+
| CountryName | NoOfGames | TotalGoalsFor | TotalGoalsAgainst |
+----------------------+-----------+---------------+-------------------+
| Algeria | 1 | 1 | 1 |
| Argentina | 4 | 5 | 1 |
| Australia | 2 | 2 | 6 |
| Belgium | 3 | 5 | 2 |
| Bosnia & Herzegovina | 1 | 3 | 1 |
| Brazil | 6 | 7 | 13 |
| Cameroon | 2 | 1 | 8 |
| Chile | 1 | 3 | 1 |
| Columbia | 3 | 7 | 1 |
| Costa Rica | 2 | 1 | 1 |
| Croatia | 1 | 1 | 3 |
| Ecuador | 1 | 0 | 0 |
| England | 1 | 1 | 2 |
| France | 3 | 5 | 1 |
| Germany | 4 | 9 | 3 |
| Ghana | 1 | 1 | 2 |
| Greece | 1 | 2 | 1 |
| Honduras | 2 | 1 | 5 |
| Iran | 1 | 0 | 0 |
| Italy | 2 | 0 | 2 |
| Ivory Coast | 1 | 2 | 1 |
| Japan | 2 | 1 | 4 |
| Mexico | 1 | 1 | 0 |
| Netherlands | 4 | 4 | 1 |
| Nigeria | 2 | 3 | 3 |
| Portugal | 1 | 2 | 1 |
| Russia | 1 | 1 | 1 |
| South Korea | 2 | 2 | 5 |
| Spain | 2 | 1 | 7 |
| Switzerland | 2 | 4 | 6 |
| Uruguay | 2 | 3 | 4 |
| USA | 2 | 2 | 3 |
| Algeria | 3 | 6 | 6 |
| Argentina | 3 | 3 | 3 |
| Australia | 1 | 1 | 3 |
| Belgium | 2 | 1 | 1 |
| Bosnia & Herzegovina | 2 | 1 | 3 |
| Brazil | 1 | 4 | 1 |
| Cameroon | 1 | 0 | 1 |
| Chile | 3 | 3 | 3 |
| Columbia | 2 | 5 | 3 |
| Costa Rica | 3 | 4 | 1 |
| Croatia | 2 | 5 | 3 |
| Ecuador | 2 | 3 | 3 |
| England | 2 | 1 | 2 |
| France | 2 | 5 | 2 |
| Germany | 3 | 9 | 1 |
| Ghana | 2 | 3 | 4 |
| Greece | 3 | 1 | 4 |
| Honduras | 1 | 0 | 3 |
| Iran | 2 | 1 | 4 |
| Italy | 1 | 2 | 1 |
| Ivory Coast | 2 | 2 | 4 |
| Japan | 1 | 1 | 2 |
| Mexico | 3 | 4 | 3 |
| Netherlands | 3 | 11 | 3 |
| Nigeria | 2 | 0 | 2 |
| Portugal | 2 | 2 | 6 |
| Russia | 2 | 1 | 2 |
| South Korea | 1 | 1 | 1 |
| Spain | 1 | 3 | 0 |
| Switzerland | 2 | 3 | 1 |
| Uruguay | 2 | 1 | 2 |
| USA | 2 | 3 | 3 |
+----------------------+-----------+---------------+-------------------+
64 rows in set (0.01 sec)
UPDATE2：每个查询提供32行，这里它们组合成64行，所以我不知道哪个属于哪个查询，你可以看到USA是最后一行对于第二个查询，每个查询然后再次以Algeria开头，其中不同的值不代表列描述。
我想要的是这样的：
+------+--------+ +------+--------+
| code | SUM(*) | | code | SUM(*) |
+------+--------+ +------+--------+
| AAA | 4 | | AAA | 4 |
| BBB | 3 | | CCC | 1 |
+------+--------+ +------+--------+
然后我进行了一些搜索，以便使用JOIN，如此处Combine results of two unrelated queries into single view所示，但是，这个场景比我的复杂得多，并且无法应用于我的场景，任何想法？
答案 0 :(得分：2)
一个视图不会产生两个结果集。但是你可以确定它们的来源：
CREATE VIEW TEAM_SUMMARY AS
SELECT 'Team1' as which,
c.country_name AS CountryName_T1, count(Team1) AS NoOfGames,
SUM(Team1_score) AS TotalGoalsFor,
SUM(Team2_score) AS TotalGoalsAgainst
FROM COUNTRY c JOIN
MATCH_RESULTS mr
ON c.country_name = mr.Team1
GROUP BY country_name
UNION ALL
SELECT 'Team2' as which,
c.country_name AS CountryNameT_2,
count(Team2) AS NoOfGames,
SUM(Team2_score) AS TotalGoalsFor,
SUM(Team1_score) AS TotalGoalsAgainst
FROM COUNTRY c JOIN
MATCH_RESULTS mr
ON c.country_name = mr.Team2
GROUP BY country_name;
注意：
SELECT DISTINCT的GROUP BY几乎总是不必要的（就像在这种情况下一样。UNION ALL。只有在您特别想要产生删除重复项的开销时才使用UNION。which来指定每行的来源。