我创建了一个允许用户上传图片的Angular2应用。我想实现一个预览选项。然而,当我试图使其成为危险时,图像并没有显现出来。我如何实现此功能?
UploadComponent.ts
import * as ng from '@angular/core';
//import { UPLOAD_DIRECTIVES } from 'ng2-uploader';
import {UploadService} from '../services/upload.service';
@ng.Component({
selector: 'my-upload',
providers:[UploadService],
template: require('./upload.html')
})
export class UploadComponent {
progress:any;
logo:any;
filesToUpload: Array<File>;
constructor(public us:UploadService){
this.filesToUpload = [];
}
upload() {
this.us.makeFileRequest("http://localhost:5000/api/SampleData/Upload", this.filesToUpload)
.then((result) => {
console.log(result);
}, (error) => {
console.error(error);
});
}
onFileChange(fileInput: any){
this.logo = fileInput.target.files[0];
}
}
Upload.html
<h2>Upload</h2>
<input type="file" (change)="onFileChange($event)" placeholder="Upload image..." />
<button type="button" (click)="upload()">Upload</button>
<img [src]="logo" alt="Preivew">
答案 0 :(得分:6)
您尝试的方式是,您不会使用fileInput.target.files[0]
获取图片网址,而是获取对象。
要获取图片网址,您可以使用FileReader
(documentation here)
onFileChange(fileInput: any){
this.logo = fileInput.target.files[0];
let reader = new FileReader();
reader.onload = (e: any) => {
this.logo = e.target.result;
}
reader.readAsDataURL(fileInput.target.files[0]);
}
答案 1 :(得分:1)
filesToUpload: Array<File> = [];
url: any;
image: any;
//file change event
filechange(fileInput: any) {
this.filesToUpload = <Array<File>>fileInput.target.files;
this.image = fileInput.target.files[0]['name'];
this.readurl_file(event);
}
//read url of the file
readurl_file(event) {
if (event.target.files && event.target.files[0]) {
const reader = new FileReader();
reader.onload = (eve: any) => {
this.url = eve.target.result;
};
reader.readAsDataURL(event.target.files[0]);
}
}
<div class="form-group">
<label for="image">Image</label>
<input type="file" class="form-control" (change)="filechange($event)" placeholder="Upload file..." >
</div>
<div class="container">
<img [src]="url">
</div>
答案 2 :(得分:0)
使用FileReader并不是一个好习惯。如果图片太大,则会因为onload函数将整个图片加载到RAM中而使浏览器崩溃。
更好的方法是使用:
url = URL.createObjectURL($event.target.files[0]);
然后,用DomSanitizer展示出来:
this.sanitizer.bypassSecurityTrustUrl(url)
所以在ts:
constructor(private sanitizer: DomSanitizer) {}
onFileChange(fileInput: any){
this.url = URL.createObjectURL($event.target.files[0]);
}
get previewUrl(): SafeUrl {
return this.sanitizer.bypassSecurityTrustUrl(this.url);
}
在html中:
<img [src]="previewUrl"/>