sql多次计数结果错误的视图

Question

mytable：

id   name    value      prob

1    andy    100         0
2    luna    0           1
3    joe     0           0
4    linda   50          3
5    rob     25          2
6    steph   100         0
7    rudy    0           0

<?php
$con = mysql_connect('localhost','root','') or die(mysql_error());
$db = mysql_select_db('mydb') or die (mysql_error());
     $sql   = "SELECT Count(*) AS total, 
                      (SELECT Count(*) FROM mytable WHERE mytable.value=100) AS filled, 
                      (SELECT Count(*) FROM mytable WHERE mytable.prob>=1) AS problems 
               FROM mytable";

     $query = mysql_query( $sql )  or die(mysql_error());
              while( $rows = mysql_fetch_array( $query ) ){
              $totals=$rows['total'];
              $fills=$rows['filled'];
              $probs=$rows['problems'];
 ?>
             TOTAL <?php echo $totals; ?>
             CLEARED <?php echo $fills; ?>
             PROBLEMS <?php echo $probs; ?>     
<?php } ?>

使用navicat生成查询..结果是正确的，但是当我在我的视图中编写代码时：

TOTAL 7
CLEARED 0
PROBLEMS 0

需要这样的结果：

TOTAL 7
CLEARED 2
PROBLEMS 3