我有下面的sql查询,执行时间太长,请求内部联接的替代方法来解决我的问题吗?因为当我删除3或4个连接时,查询执行得更快。
SELECT p.first_name, p.last_name, p.x, p.dob,'name', w.id_table1, w.type, w.secondary_type, w.primary_location, w.onset, w.created_at, av.item as table1_edge , av1.item as sdf ,av2.item as sd, av3.item as odor, av4.item as xz, av5.value as xxx , av9.item as cc, av10.item as cxz
FROM table1 w
INNER JOIN table2 a ON w.id_table1 = a.table1_id_table1
INNER JOIN table3 av ON a.id_table2 = av.id_table3 and av.sub_group = 'x1'
INNER JOIN table3 av1 ON a.id_table2 = av1.id_table3 and av1.sub_group = 'x2'
INNER JOIN table3 av2 ON a.id_table2 = av2.id_table3 and av2.sub_group = 'x3'
INNER JOIN table3 av3 ON a.id_table2 = av3.id_table3 and av3.sub_group = 'x4'
INNER JOIN table3 av4 ON a.id_table2 = av4.id_table3 and av4.sub_group = 'x5'
INNER JOIN table3 av5 ON a.id_table2 = av5.id_table3 and av5.sub_group = 'x6' and av6.item like 's%'
INNER JOIN table3 av6 ON a.id_table2 = av6.id_table3 and av6.sub_group = 'x7' and av6.item like 'x%'
INNER JOIN table3 av7 ON a.id_table2 = av7.id_table3 and av7.sub_group = 'x8' and av6.item like 'z%'
INNER JOIN table3 av8 ON a.id_table2 = av8.id_table3 and av8.sub_group = 'x9' and av6.item like 'y%'
INNER JOIN table3 av9 ON a.id_table2 = av9.id_table3 and av9.sub_group = 'x10'
INNER JOIN table3 av10 ON a.id_table2 = av10.id_table3 and av10.sub_group = 'x11'
INNER JOIN table0 p ON w.table0_id_table0 = p.id_table0
where w.created_at between '1991-12-09 00:00:00' and now() and user_id_user = 4
数据:
的 table0
FIRST_NAME
姓氏
DOB
...
table1
id_table1
类型
secondary_type
...
答案 0 :(得分:1)
也许你可以让你更简单地查询:
SELECT p.first_name, p.last_name, p.x, p.dob,'name',
w.id_table1, w.type, w.secondary_type, w.primary_location,
w.onset, w.created_at, av.item,
IF(av.sub_group='x1', 1, 0) as val_x1,
IF(av.sub_group='x2', 1, 0) as val_x2,
IF(av.sub_group='x3', 1, 0) as val_x3,
..........
IF(av.sub_group='x11', 1, 0) as val_x11
FROM table1 w
INNER JOIN table2 a ON w.id_table1 = a.table1_id_table1
left join table3 av on a.id_table2 = av.id_table3
INNER JOIN table0 p ON w.table0_id_table0 = p.id_table0
where w.created_at between '1991-12-09 00:00:00'
and now() and user_id_user = 4
and ( (av.sub_group in ('x1', 'x2', 'x3', 'x4', 'x5', 'x10', 'x11'))
or (av.sub_group='x6' and av.item like 's%')
or (av.sub_group='x7' and av.item like 'x%')
or (av.sub_group='x8' and av.item like 'z%')
or (av.sub_group='x9' and av.item like 'y%')
)
我们只使用表JOIN
制作一个table3
,并将所有条件移至where
子句中。使用val_x1
.... val_x11
,我们可以知道av.item
中的哪一个值。
答案 1 :(得分:1)
您是否尝试使用子查询代替需要更长时间执行的内部联接?
示例:
select a.id, b.id, c.id
from table a
inner join (
select id
from tableb
where b = 'x1'
) as b on b.id = a.id
inner join (
select id
from tablec
where c = 'x2'
) as c on c.id = a.id
答案 2 :(得分:0)
您似乎以EAV格式存储内容(entity-attribute-value)。如果你不明白这意味着什么,你可以查看维基百科上的定义。
一种解决方案是使用聚合:
SELECT p.first_name, p.last_name, p.x, p.dob, 'name',
w.id_table1, w.type, w.secondary_type, w.primary_location,
w.onset, w.created_at,
MAX(CASE WHEN av.sub_group = 'x1' THEN av.item END) as table1_edge,
MAX(CASE WHEN av.sub_group = 'x1' THEN av.item END) as sdf,
. . .
FROM table1 w INNER JOIN
table2 a
ON w.id_table1 = a.table1_id_table1 INNER JOIN
table3 av
ON a.id_table2 = av.id_table3
WHERE av.sub_group IN ('x1', 'x2', . . . ) AND
w.created_at between '1991-12-09' and now() AND
user_id_user = 4
GROUP BY p.first_name, p.last_name, p.x, p.dob,
w.id_table1, w.type, w.secondary_type, w.primary_location, w.onset, w.created_at;
您还需要适当的索引。我猜这些是table1(user_id_user, created_at, id_table1)
和table3(id_table3, sub_group, item)
。