Postgres数据为XML格式

Question

我在postgres中有这个：

copy (select  xmlelement(name atccode, xmlattributes(secondary_label as code), 
xmlelement(name description, secondary_label || ' - ' || label)) 
from study_subject where study_id=28 order by label) 
to 'includes/output10.xml';

它在output10.xml文件中给出了以下内容：

<atccode code="6995">
  <description>6995 - Atkins, Dian</description>
</atccode>
<atccode code="130">
  <description>130 - Bailey, Howard H, MD</description>
</atccode>

我怎样才能得到这个：

<atclist>
<atccode code="6995">
  <description>6995 - Atkins, Dian</description>
</atccode>
<atccode code="130">
  <description>130 - Bailey, Howard H, MD</description>
</atccode>
</atclist>

Answer 1

解决方案：

COPY (SELECT xmlelement(name atclist, xmlagg(xmlelement(name atccode,
xmlattributes(description as code), 
xmlelement(name description, description)))) 
FROM INVlist) 
TO 'path/output12.xml';