Question

我正在尝试创建一个表单，我在这些行中出错。

 else 
 {
  //report the errors.

 echo '<h1> Err... </h1>
 <p> The following error(s) have occured</p>';

 foreach ($errors as $msg)
     {
   echo "--$msg<br />\n";
  }
  echo '</p><p>Please Try Again.</p><p><br/></p>';

 }

那么，有什么不对？这是错误消息 -

... ERR

发生了以下错误 -

注意：未定义的变量：错误   第107行的C：\ wamp \ www \ password.php

警告：提供的参数无效   foreach（）在C：\ wamp \ www \ password.php中   在107行，请再试一次。

我将错误设置为数组。

我上面的代码 -

如果（isset（$ _ POST [ '提交']）） {

require_once('C:\wamp\www\connect.php');
//connecting to db

$errors = array();

if (empty($_POST['email']))

{
    $errors[]='Please enter a valid email address.';
}

这是我的完整代码 -

//forgot password update

include('C:\wamp\www\header.html');

//check if form has been submitted
require_once('C:\wamp\www\connect.php');
    //connecting to db



if(isset($_POST['submitted'])) {
    $errors = array();


    if (empty($_POST['email']))

    {
        $errors[]='Please enter a valid email address.';
    }

    else
    {
      $e = mysqli_real_escape_string($db_name,trim($_POST['email']));
    }

    //check for current password
    if (empty($_POST['password']))

    {
        $errors[]='Current password does not match.';
    }

    else
    {
      $p = mysqli_real_escape_string($db_name,trim($_POST['password']));
    }

    //check for a new password and match with confirm pass.

    if(!empty($_POST['password1']))
    {
        if($_POST['password1'] != $_POST['cpass'])
        {
            $errors[] = 'The entered password and confirm password do not match.';
        }
        else
        {
            $np=mysqli_real_escape_string($db_name,trim($_POST['password1']));
        }
    }
    if(empty($errors))
    //if everything is fine.

    //verify the entered email address and password.

    $q="SELECT username FROM users WHERE (email='$e' AND password=SHA1('$p'))";
    $r=@mysqli_query($db_name,$q);
    $num = @mysqli_num_rows($r);
    if($num==1)
    //if it matches.

    //get user id
    {
    $row=mysqli_fetch_array($r, MYSQLI_NUM);

    //udpdate query.

    $q="UPDATE users SET password= SHA1('$np') WHERE username=$row[0]";

    $r=@mysqli_query($db_name, $q);

    if (mysqli_affected_rows($db_name) ==1)

    {
        echo '<h3>Your password has been updated.</h3>';
    }

    else {
        echo '<h3>Whops! Your password cannot be changed due a system error. Try again later. Sorry</h3>';

    echo '<p>' .mysqli_error($db_name). 'Query:' . $q.'</p>';
    }


    exit();
    }
    else 
    {

        //invalid email and password

        echo 'The email address and password do not match';
    }

}
    else 
    {
        //report the errors.

    echo '<h1> Err... </h1>
    <p> The following error(s) have occured</p>';

    foreach ($errors as $msg)
        {
            echo "--$msg<br />\n";
        }
        echo '</p><p>Please Try Again.</p><p><br/></p>';

    }


    ?>

Answer 1

没有名为$errors的数组。你必须进一步查看你的脚本。

您可以使用

修复错误消息

if (!empty($errors) and (is_array($errors)))
 foreach ($errors as $msg)

Answer 2

foreach循环超出了定义$error数组的范围。

您的代码简而言之：

if(isset($_POST['submitted'])) {
    $errors = array();
} else {
    foreach($errors as $error)
}

如果未设置$_POST，则未定义$errors。

Answer 3

将“$ errors = array（）”的声明移到行“if（isset（$ _ POST ['submitted']））{{ “一切都应该运转正常！

Answer 4

你有两个问题。第一个是空的/不存在的数组的原因，第二个是缺乏对它的测试。

首先，您正在测试if块内的错误，然后在else块内循环它们。

if (isset($_POST['submitted'])) {
  // create errors array and set errors
} else {
  // loop through array of errors
}

因此，如果设置了错误，脚本就不会进入循环。如果脚本进入循环，则不会设置错误。

第二个是你应该在测试数组后才进入foreach循环：

if (!empty($errors) && is_array($errors)) { // use this line and get rid of the else.
  foreach ($errors as $msg) {
        echo "--$msg<br />\n";
  }
  echo '</p><p>Please Try Again.</p><p><br/></p>';
 } // and close it.

Answer 5

基本上，这里发生的是你在定义之前使用$ errors。

可能需要在脚本顶部附近设置“$ errors = array（）”，以便它始终至少为空数组。

foreach无效参数和未定义变量

5 个答案: